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Unformatted text preview: 0.85)]j2(2.7) = 1.74 cm. (The negative root can be discarded since x ~ 0.) (b) The maximum kinetic energy occurs at the point where U is a niinhrtum; that is, dU I dx 2axo  b 0, or Xo = b/2a = O.778cm. (c) Vmax = J2Kmax/me = J2(E  Urnin)/me. Now, Umin = xo{axo  b} = = = = = = b2/4a = (4.2 fJ cm 24{2.7 fJ cm2) = 1.63 fJ, so that vmax = 2(0.85 + 1.63) fJ/{9.llxlO31 kg) = 7.38x 107 m/s. u Problem
80. Show that the rope in Example 86 will cease to be taut when the rope has caught on the rock and makes an angle ()= cosl [~~ (cos 00 + ~ 19] Problem 81. Solution. with the vertical. Show that your anSM::f is consistent with that of Problem 33....
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 Spring '08
 WORMER
 Physics, Conservation Of Energy, Energy, Work

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