{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Then the work energy theorem requires that wr 11u mgyb

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: acement along each slope is == y j sin () (measured Assume that the surface is horizontal, so th~t there are no changes in the block's potential energy ~11U = 0) and the force of friction on it is !k ::::: -ILkN;::::: ~I-'kmg (opposite to the direction of motion along the x-axis). If the block crosses the entire region from al ::::: 1 m to X2::::: 2 m, the work-energy theorem deman1s that Wnc = - . or . Xl ~ 1 l a X2 I-'kmg dx ::::: 11K = ~m(v~. - vi) '. 1 1 ' j 2 e vi - v~ = 2g (ax2 + bx +c)dx b 2m 1m Xl = 2g l 3X3 + '2X2 +CX = 6.53,'! m /s 2 2 (The given values of a, b;and c were used. ) liThe minimum speed at the start of the region isi:the value FIGURE 8-39 Problem 59 Solution. .~ CHAPTER8 137 ~bottom of both slopes), so that work done by, em each slope is 11. = (_p,'!:axmg cos fJ) x 'If J= _p,raXmgy cot fJ. Then the work-energy :: ).becomes -mg(YA - YB) = _p,;:axmgx Q~+ YBcotOB), from which p,'!:a.x be can ax = (950 - 840)/(950 cot 27 + )iecl: p,r )35)= 0.036. (0.19 kg)(9.8 m/s2)(0.85 m) = -0.427 J. Sin...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern