What is the maximum speed at which the car can

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: sses), y2 = For + mgy. (This is Equation 8-7 for points A and B in the .... sketch.) Since the gravitational potential energy . hange is negligible compared to the other terms, k ':::! c .. m(vB/y)2 = 103 kg(2.4 km/s=15 m)2 ~ 25.6 MN/~. (Note: The surface gravity on the moon 18 1.62 m/s , o the maximum change in potential energy of a s packet is only mgy = 24.3kJ, while its kinetic energy, lmv~ = 2.88 OJ, is more than 106 times larger. likewise, the gravitational potential energy of the spring is negligible.) !k !mv1 Solution The maximum energy stored by thesprings,~kx2, ;; without incurring damage, is equal to the maximum kinetic energy,!mv2, of the car before a collision. (We assume a level road and horizontal collision so that there is no change in the car's -gravitational potential energy.) Thus, ~kX2 == ~mv2, or v = Jk/m x = " J(7.0xl05 N/m)/(1400 kg)(O.16 m) = 3.58 m/s == i" 12.9 km/h. i: Problem , 32. A block slides on the frictionless loop-the-loop " track shown...
View Full Document

This note was uploaded on 07/27/2009 for the course PHYSICS 101 taught by Professor Wormer during the Spring '08 term at NYU Poly.

Ask a homework question - tutors are online