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Becomes mgya yb paxmgx q ybcotob from which pax

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Unformatted text preview: ce Ko/ ILlEI = 5.27, five complete crossings are made, leaving the block with energy Ko. - 5j..6.EI = 0.113 J on the curved rise side. This remaining energy is sufficient to move the block a distance s = 0.113 J ..;J-tkmg = 22.5 em towards point 0, so the block comes to rest 85 - 22.5 = 62.5 ern to the right of point O. g slides back and forth in a hemispherical lof 11 cm radius, starting from rest at the as shown in Fig. 8-40. The bowl is frictionless pt for a L5-cm-wide sticky patch at the tom, where the coefficient of friction is 0.6l. ,",many times does the bug cross the sticky Jf6 5""''1 FrictioDleu FIGURE (J P~~:J:1 Frictionless 8-41 Problem 61 Solution. Section 8-7: Conservation of Energy and Mass-Energy Problem 62. Two deuterium nuclei fuse to form a helium nucleus. Each deuterium has mass 3.344x 10-27 kg, and the helium has mass 6.645xlO-27 kg. Find the energy released in this reaction. FIGURE 8-40 Problem 60. Solution The difference in mass between two deuterium nuclei and one helium nucleus...
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