PS_9_SIMAN - queue and a single frequent agent If the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
IE 306.01 PS#9 13.05.09 1. There are two types of parts: aluminum and steel. Aluminum parts arrive according to an exponential distribution with a mean of 5 minutes and steel parts arrives exponentially with a mean of 8 minutes. Both parts are drilled and before the drilling machine there is a storage area with a capacity of 10. Aluminum parts have a normally distributed drilling time with mean 4 minutes and standard deviation 1 minute. Steels parts have also normal drilling time with mean 12 minutes and standard deviation 3 minutes. We want to count how many number of parts from each type are drilled in 8 hours. Build the corresponding SIMAN model. 2. Customers arrive to a service company with exponentially distributed inter arrival times. 80% of the customers are regular customers and 20% of them are frequent customers. Regular customers are served by regular agents and frequent customers are served by frequent agent having separate queues. There are 4 regular agents (all have the same
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: queue) and a single frequent agent. If the frequent agent is busy and if there are not more than 2 customers in the queue of the regular agents, frequent customer in the queue changes his/her queue and moves to the regular queue. Regular customers and frequent customers have a service time N(10, 4) and N(7, 2) respectively(in minutes). This company works 16 hours a day (between 08:00-00:00). Inter arrival time (in minutes) of the customers follow EXPO(2) between 08:00-16:00 and EXPO(4) between 16:00-24:00. Besides, frequent agent is closed after 16:00 so as of 16:00 frequent customers are also served by the regular agents. Write a SIMAN code that runs this company for a day and gives the following statistics: total time spent in the system for each customer type the number of customers that change their queue average number of busy regular agents average number of busy frequent agents average number of customers in the regular queue average number of customers in the frequent queue...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online