Spring 09 lecture 05

Spring 09 lecture 05 - Renaturation Kinetics of Human DNA...

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Renaturation Kinetics of Human DNA > 100,000 copies 10-100,000 copies How would this graph look if we plotted % of double-stranded DNA on y axis?
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E. Coli Genome vs. Calf Genome Keep in mind: 0% reassociated (ds) DNA is the same as 100% denatured (ss) DNA everything is still ss E. Coli : no repetitive sequences; the whole genome is one unique sequence Difficult for sequences to find complementary sequences Once they are found – fast re-association Calf: lots of repetitive sequences – fast re- association Some sequences unique – slow re-association at the beginning but gets faster (those unique sequences resemble/are comparable to E. coli genome) fast middle slow
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Highly repetitive : there is lots of them (1000-100000), they are able to find each other really easylly fast renaturation . Role unknown. Moderately repetitive : moderate # (10-1000), find each other with little difficulties, need more time middle renaturation . Some of them lack coding function. Some of them – code for different gene families: globin genes, immunoglobulin genes, genes for tRNAs and rRNAs etc. Unique : one to few copies, have lots of difficulties to find each other during renaturation slow renaturation . Mostly protein coding sequences. slow middle fast
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Determining Genome Size by Cot Analysis FYI: (for example E. coli )
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Is complexity of genome in correlation with the apparent morphological complexity of the organism ? N = haploid chromosome number C = DNA content/haploid cell C varies greatly among phyla General increase from prokaryotes to eukaryotes Large differences within eukaryotes More DNA present than we can account for. .. C Value Paradox
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This note was uploaded on 08/03/2009 for the course BIOL BIOL308 taught by Professor Miskovic during the Spring '09 term at Waterloo.

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Spring 09 lecture 05 - Renaturation Kinetics of Human DNA...

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