HW1 - Homework 1 Jan 25 2007 1 a At constant pressure q p = Δ H and Δ H does not depend on paths q p = Δ H(20 ◦ C = Δ(100 ◦ C C p `(100 20

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Unformatted text preview: Homework 1 Jan. 25, 2007 1. a. At constant pressure, q p = Δ H and Δ H does not depend on paths. q p = Δ H (20 ◦ C ) = Δ(100 ◦ C ) + C p ( ` )(100- 20) + C p ( g )(20- 100) = Δ(100 ◦ C ) + ( C p ( ` )- C p ( g ))(100- 20) = 2257 + (4 . 18- 1 . 874) × 80 = 2441 . 48 kJ b. Δ T hiker = q p 60 × 4 . 18 = 9 . 73 K c The reaction is sucrose(s) + 12O 2 ( g ) → 12CO 2 + 11H 2 O . From TABLE A.5 and 7, Δ H = 11 × (- 285 . 83) + 12 × (- 393 . 51)-- (- 2222 . 1) =- 5644 kJ / mol Molecular weight of sucrose is 342 g/mol. Thus, the amount of sucrose which replace the heat of evaporating 1.00 L of water is 342 × 2441 . 48 5644 = 148 g . Note that the Δ ¯ H of sucrose given in TABLE A.7 should be for solid . 3. a. w = 10 × g × 10 = 10 × 9 . 8 × 10 = 980 J b. w = 6 × 5 . 5 × 7200 = 237600 J 1 c. w = 1 2 k Δ x 2 = 1 2 × 5 (10 . 5- 10 . 0) × 10- 2 × (10- 2 ) 2 = 0 . 05 J d....
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This note was uploaded on 08/03/2009 for the course BME 100 taught by Professor Yuan during the Spring '07 term at Duke.

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HW1 - Homework 1 Jan 25 2007 1 a At constant pressure q p = Δ H and Δ H does not depend on paths q p = Δ H(20 ◦ C = Δ(100 ◦ C C p `(100 20

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