HW3 - Homework 3 Feb. 8, 2007 1. a. By using the dilute...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Homework 3 Feb. 8, 2007
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
1. a. By using the dilute solution standard states, K = [G-1-P][ADP] [G][ATP] = 770 × 10 - 4 10 - 3 = 77 . 0 where G-1-P and G refer to glycerol-1-phosphate and glycerol, respectively. Δ G 0 0 298 = - RT ln K = - 8 . 314 × 298 × ln 77 = - 10 . 76 kJ mol - 1 . b. 1 : G + ATP G-1-P + ADP , Δ G 0 0 1 = - 10 . 76 2 : ADP + D i G-1-P + H 2 O, Δ G 0 0 2 = 31 . 10 1 + 2 : G + P i G-1-P + H 2 O. Hence, Δ G 0 0 298 = Δ G 0 0 1 + Δ G 0 0 2 = - 10 . 76 + 31 . 10 = 20 . 2 kJ mol - 1 K = e - Δ G 0 0 298 RT = 2 . 9 × 10 - 4 . 2. a. Δ G 0 = Δ G 0 0 + RT ln [ADP][P i ] [ ATP ] = - 31 . 0 + 8 . 314 × 10 - 3 × 298 × ln 0 . 5 × 10 - 3 × 2 . 5 × 10 - 3 1 . 25 × 10 - 3 = - 48 . 1kJ mol - 1 . b. At constant temperature and pressure, w max = w rev = Δ G 0 = - 48 . 1 kJ mol - 1 . 1
Background image of page 2
c. Let PC and C be phosphocreatine and creatine, respectively. 1 : PC + H 2 O C + P i , Δ G 0 0 1 = - 43 . 1 2 : P i + ADP ATP + H 2 O , Δ G 0 0 2 = 31 . 0 1 + 2 : PC + ADP
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 08/03/2009 for the course BME 100 taught by Professor Yuan during the Spring '07 term at Duke.

Page1 / 6

HW3 - Homework 3 Feb. 8, 2007 1. a. By using the dilute...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online