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Unformatted text preview: (b) Chapter 5, Problem 71. or this problem, note that for a secondorder circuit with a constant forcing function K : d 2 y dt 2 + 2 n dy dt + 2 n y = K n with > 0 the following calculation applies: lim t y ( t ) = K urthermore, if the system is underdamped , that is, if 0 < < 1, a = n , d = n r 1 2 , and y ( t ) = K p 1eat p cos( d t ) + a d sin( d t ) PP , t > and there is no energy stored initially, the peak time and value at that time can be given by: t peak = n r 1 2 = d y ( t peak ) = K (1 + eat peak ) = K p 1 + e 1 2 P Part II: (a) Chapter 5, Problem 73. (b) Chapter 5, Problem 74. Part III: (a) Chapter 8, Problem 1. (b) Chapter 8, Problem 5. (c) Chapter 8, Problem 7. Part IV: (a) Chapter 8, Problem 10. (b) Chapter 8, Problem 13. Copyright 2009, Gustafson Hwk 9 1...
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This note was uploaded on 08/03/2009 for the course BME 153 taught by Professor Malkin during the Spring '07 term at Duke.
 Spring '07
 MALKIN

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