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Unformatted text preview: Ch. 3 Kinematics in 2D Now lets consider the concepts of displacement , velocity , and acceleration in 2 dimensions. o f x x x = t x x t x v o f = = 1D o f r r r v v v = t r r t r v o f v v v v = = 2D t v v t v a o f = = 2 2 1 at t v x x o o f + + = a v v x o f 2 2 2 = t v v t v a o f v v v v = = 2 2 1 t a t v r r o o f v v v v + + = a v v r o f v v v v 2 2 2 = In general, for 2D, displacements, velocities, and accelerations will have components in both the x and ydirection. Concepts from Ch. 1 Thus, y x r r r v v v + = y x v v v v v v + = y x a a a v v v + = 2 2 1 t a t v x x x o o f x + + = 2 2 1 t a t v y y y o o f y + + = We get 2 equations of motion under constant acceleration one for the x direction, and one for the ydirection. Example : A car drives 60 o N of E at a constant speed of 35 m/s. How far east has the car traveled after 10 s? E, x N, y v = 35 m/s 60 o We can break the velocity down into its x and ycomponents. v y v x Now I can calculate the values for v x and v y : o x v v 60 cos = o y v v 60 sin = m/s 5 . 17 ) m/s)( 35 ( 2 1 = = m/s 3 . 30 ) m/s)( 35 ( 2 3 = = For distance in the xdirection (east) we use v x : t v x x = m 175 s) m/s)(10 17.5 ( = = 3.3 Projectile Motion Now lets analyze the motion of projectiles launched into the air, but this time, the motion is not completely vertical 2D projectile motion.the motion is not completely vertical 2D projectile motion....
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This note was uploaded on 08/04/2009 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Acceleration

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