lecture 6

lecture 6 - Parallel plate capacitor A s E B 9 V 6 V The...

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Parallel plate capacitor A B Δ s + + + - - E The positive plate is at a potential of +9 V and the negative plate is at 0 V. + - - +9 V 0 V What would the equipotential surfaces look like between the plates? +3 V +6 V They would be a parallel set of planes! Let the plates be separated by a distance Δ s. pp y The electric field is then [ ] V E Δ = = istance hange in voltage Change [ ] s Δ distance in Change This is called the electric field gradient . hus the electric field also has units of Thus, the electric field also has units of [ ] m V /
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19.5 Capacitors Two oppositely charged conductors separated by some small distance. Volts We can charge the plates by connecting them to a battery: + - + - The higher the voltage on our battery, the more charge we can put on each plate. Q + + - - Thus, V Q Make this an equality: CV Q = C is a new quantity called the Capacitance . +Q -Q Units? [] [ ] F Farad V C Voltage Charge = = = = V Q C *A farad is a very large capacitance . We often use microfarads ( μ f) and picofarads (pf). 0 - 0 - 2 1×10 6 F 1×10 12 F The larger the capacitance, the more charge it will hold!
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Dielectrics e can fill the space between the plates with some insulating material say air We can fill the space between the plates with some insulating material, say air, oil, paper, rubber, plastic, etc. This material is called a dielectric . Dielectric + + - - E o So what effect does the dielectric have on the field between the plates? - + - + E + - + - Since the dielectric is an insulator, the charges in it aren’t free to move, but they can separate slightly within each atom: - + - + Each one of these atoms now produces a small
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lecture 6 - Parallel plate capacitor A s E B 9 V 6 V The...

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