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Unformatted text preview: AP Physics C: Mechanics
2001 FreeResponse Questions The materials included in these files are intended for use by AP teachers for course
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Copyright © 2001 by College Entrance Examination Board. All rights reserved. College Board, Advanced Placement Program, AP, and the acorn logo
are registered trademarks of the College Entrance Examination Board. AP® PHYSICS C EQUATIONS FOR 2001
MECHANICS u = u0 + at
1
x = x0 + u0 t + at 2
2
2
2
u = u0 + 2a x − x0 0 ∑ F = Fnet = ma
dp
F=
dt
J = F dt = Dp
p = mv
F fric ≤ mN I IF W= • ds 1
mu 2
2
dW
P=
dt
DUg = mgh
K= ac = t u 2 = w2r
r =r×F
∑ t = t net = Ia I I = r 2 dm = ∑ mr 2
rcm = ∑ mr ∑ m
u = rw
L = r × p = Iw
1
K = Iw 2
2
w = w0 + at
q = q0 + w0 t + 1 at 2
2
Fs = − kx
1
Us = kx 2
2
2p
1
T=
=
w
f
m
Ts = 2 p
k
l
Tp = 2 p
g
Gm1m2
$
FG = −
r
r2
Gm1m2
UG = −
r 5 a=
F=
f=
h=
I=
J=
K=
k=
l=
L=
m=
N=
P=
p=
r=
s=
T=
t=
U=
u=
W=
x=
m=
q=
t=
w=
a= acceleration
force
frequency
height
rotational inertia
impulse
kinetic energy
spring constant
length
angular momentum
mass
normal force
power
momentum
radius or distance
displacement
period
time
potential energy
velocity or speed
work
position
coefficient of friction
angle
torque
angular speed
angular acceleration ELECTRICITY AND MAGNETISM
1 q1q2
4p 0 r 2
F
E=
q
Q
E • dA =
F= 0 dV
dr
1
V=
4p 0
E=− ∑ rii
q i UE = qV = 1 q1q2
4p 0 r Q
V
k 0A
C=
d
C p = ∑ Ci
C= i 1
1
=∑
Cs
Ci
i
dQ
I=
dt
1
1
Uc = QV = CV 2
2
2
rl
R=
A
V = IR
Rs = ∑ Ri 1
=
Rp ∑ i i 1
Ri P = IV
F M = qv × B
B • d l = m0 I I Id l × B F= Bs = m0 nI
fm = IB • dA dfm
dt
e = − L dI
dt
12
U L = LI
2 e =− 2 A=
B=
C=
d=
E=
e=
F=
I=
L=
l=
n= area
magnetic field
capacitance
distance
electric field
emf
force
current
inductance
length
number of loops of wire
per unit length
P = power
Q = charge
q = point charge
R = resistance
r = distance
t = time
U = potential or stored energy
V = electric potential
u = velocity or speed
r = resistivity
fm = magnetic flux
k = dielectric constant AP® PHYSICS C EQUATIONS FOR 2001
GEOMETRY AND TRIGONOMETRY
Rectangle
A = bh
Triangle
1
A = bh
2
Circle
A = pr 2
C = 2 pr
Parallelepiped
V = lwh
Cylinder
V = pr 2 l
S = 2 prl + 2 pr 2
Sphere
4
V = pr 3
3
S = 4 pr 2
Right Triangle
a 2 + b2 = c2
a
sin q =
c
cos q = area
circumference
volume
surface area
base
height
length
width
radius c a
90 q
b b
c tan q = A=
C=
V=
S=
b=
h=
l=
w=
r= a
b CALCULUS
df
d f du
=
dx
du dx
• 27
27 dn
n −1
x = nx
dx
dx
e = ex
dx
1
d
(1n x) =
dx
x
d
(sin x) = cos x
dx
d
(cos x) = − sin x
dx
1 n +1
xn dx =
x , n ≠ −1
n +1
ex dx = ex I
I I dx
= 1n x
x
cos x dx = sin x I
I sin x dx = − cos x
3 2001 AP® PHYSICS C: MECHANICS FREERESPONSE QUESTIONS
PHYSICS C
Section II, MECHANICS
Time—45 minutes
3 Questions
Directions: Answer all three questions. The suggested time is about 15 minutes for answering each of the questions,
which are worth 15 points each. The parts within a question may not have equal weight. Show all your work in the
pink booklet in the spaces provided after each part, NOT in this green insert. Mech 1.
A motion sensor and a force sensor record the motion of a cart along a track, as shown above. The cart is given a
push so that it moves toward the force sensor and then collides with it. The two sensors record the values shown
in the following graphs. (a) Determine the cart’s average acceleration between t = 0.33 s and t = 0.37 s.
(b) Determine the magnitude of the change in the cart’s momentum during the collision.
(c) Determine the mass of the cart.
(d) Determine the energy lost in the collision between the force sensor and the cart. Copyright © 2001 by College Entrance Examination Board. All rights reserved.
Advanced Placement Program and AP are registered trademarks of the College Entrance Examination Board. GO ON TO THE NEXT PAGE.
4 2001 AP® PHYSICS C: MECHANICS FREERESPONSE QUESTIONS
Mech 2.
An explorer plans a mission to place a satellite into a circular orbit around the planet Jupiter, which has mass
M J = 1.90 10 27 kg and radius R J = 7.14 10 7 m.
(a) If the radius of the planned orbit is R, use Newton’s laws to show each of the following.
i. The orbital speed of the planned satellite is given by u =
ii. The period of the orbit is given by T = GM J
.
R 4p 2 R 3
.
GM J (b) The explorer wants the satellite’s orbit to be synchronized with Jupiter’s rotation. This requires an equatorial
orbit whose period equals Jupiter’s rotation period of 9 hr 51 min = 3.55 × 104 s. Determine the required
orbital radius in meters.
(c) Suppose that the injection of the satellite into orbit is less than perfect. For an injection velocity that differs
from the desired value in each of the following ways, sketch the resulting orbit on the figure. (J is the center
of Jupiter, the dashed circle is the desired orbit, and P is the injection point.) Also, describe the resulting
orbit qualitatively but specifically.
i. When the satellite is at the desired altitude over the equator, its velocity vector has the correct
direction, but the speed is slightly faster than the correct speed for a circular orbit of that radius. ii. When the satellite is at the desired altitude over the equator, its velocity vector has the correct
direction, but the speed is slightly slower than the correct speed for a circular orbit of that radius. Copyright © 2001 by College Entrance Examination Board. All rights reserved.
Advanced Placement Program and AP are registered trademarks of the College Entrance Examination Board. GO ON TO THE NEXT PAGE.
5 2001 AP® PHYSICS C: MECHANICS FREERESPONSE QUESTIONS Mech 3.
A light string that is attached to a large block of mass 4m passes over a pulley with negligible rotational inertia
and is wrapped around a vertical pole of radius r, as shown in Experiment A above. The system is released from
rest, and as the block descends the string unwinds and the vertical pole with its attached apparatus rotates. The
apparatus consists of a horizontal rod of length 2L, with a small block of mass m attached at each end. The
rotational inertia of the pole and the rod are negligible.
(a) Determine the rotational inertia of the rodandblock apparatus attached to the top of the pole.
(b) Determine the downward acceleration of the large block.
(c) When the large block has descended a distance D, how does the instantaneous total kinetic energy of the
three blocks compare with the value 4mgD ? Check the appropriate space below.
____ Greater than 4mgD ____ Equal to 4mgD ____ Less than 4mgD Justify your answer. Copyright © 2001 by College Entrance Examination Board. All rights reserved.
Advanced Placement Program and AP are registered trademarks of the College Entrance Examination Board. GO ON TO THE NEXT PAGE.
6 2001 AP® PHYSICS C: MECHANICS FREERESPONSE QUESTIONS The system is now reset. The string is rewound around the pole to bring the large block back to its original
location. The small blocks are detached from the rod and then suspended from each end of the rod, using strings
of length l. The system is again released from rest so that as the large block descends and the apparatus rotates,
the small blocks swing outward, as shown in Experiment B above. This time the downward acceleration of the
block decreases with time after the system is released.
(d) When the large block has descended a distance D, how does the instantaneous total kinetic energy of the
three blocks compare to that in part (c) ? Check the appropriate space below.
____ Greater ____ Equal ____ Less Justify your answer. END OF SECTION II, MECHANICS Copyright © 2001 by College Entrance Examination Board. All rights reserved.
Advanced Placement Program and AP are registered trademarks of the College Entrance Examination Board. GO ON TO THE NEXT PAGE.
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This note was uploaded on 08/05/2009 for the course PHYS 101 taught by Professor Reich during the Spring '08 term at Johns Hopkins.
 Spring '08
 Reich
 Physics, mechanics

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