M7solns4 - Solutions to Problems in Chapter Four Test Your...

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Solutions to Problems in Chapter Four Test Your Understanding Problems T4.3-1 The session is ± x = [5,-3,18,4];y = [-9,13,7,4]; ± z = ~y>x z= 0100 ± z=x&y 1111 ± z=x|y ± z = xor(x,y) 0000 T4.3-2 The script fle is identical to that used in Example 4.3-1 except For the line u= find(~(h<4|v>17)); . v0 = 20;g = 9.81;A = 40*pi/180; t_hit = 2*v0*sin(A)/g; t = [0:t_hit/100:t_hit]; h = v0*t*sin(A)-0.5*g*t.^2; v = sqrt(v0^2-2*v0*g*sin(A)*t+g^2*t.^2); u = find(~(h<4|v>17)); t_1 = (u(1)-1)*(t_hit/100) t_2 = u(length(u)-1)*(t_hit/100) The results are t 1 =0 . 5766 and t 2 =2 . 0443. Thus h< 4or v> 17 For t<t 1 and For t>t 2 . T4.4-1 Using x = 13 as a test case, the fle is: x=13; if x>10 y = log(x) if y >= 3 z = 4*y elseif y > 2.5 z = 2*y 4-1
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else z=0 end else y = 5*x z = 7*x end T4.4-2 Note that the asin(x) function returns the correct value (in radians) only if x is in the Frst or fourth quadrant. Note also that it is possible to give incompatible values for q and x . ±or example, q cannot equal 1 if x< 0. The following script Fle protects against this error. if x >= 0&x<1 if q==1 y = asin(x)*180/pi; elseif q==2 y = asin(x)*180/pi + 270; end if q==3|q==4 disp( ± Incompatible values of x and q ± ) else disp(y) end elseif x<0&x>-1 if q==4 y = asin(x)*180/pi; else y = asin(x)*180/pi -90; end if q==1|q==2 disp( ± Incompatible values of x and q ± ) else disp(y) end else disp( ± The magnitude of x is greater than 1 ± ) end 4-2
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T4.5-1 The script fle is m=0; for q = 0:6:18 m = m+1; n=0; for r = 4:4:12 n = n+1; A(m,n) = r+q; end end T4.5-2 The script fle is [m,n] = size(A); for c = 1:n x=0; for r = 1:m x = x + A(r,c); end sum_A(c) = x; end disp(sum_A) T4.5-3 The script fle is x=49; k=1; while x>0 y = sqrt(x) k = k+1; x = 50 - k^2; end 4-3
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T4.5-4 The script fle is error = 0; x=0; while error < 1 x = x + 0.01; approx = 1 + x + x^2/2 + x^3/6; error = 100*(exp(x) - approx)/exp(x); end disp(x) T4.6-1 The script fle is angle = input( ± Enter an angle in degrees. ± ) switch angle case 45 disp( ± Angle is in first quadrant ± ) case -45 disp( ± Angle is in second quadrant ± ) case 135 disp( ± Angle is in third quadrant ± ) case -135 disp( ± Angle is in fourth quadrant ± ) otherwise disp( ± Quadrant is unknown. ± ) end T4.8-1 The 0.75 in the matrix should be replaced with 0.70. T4.8-2 Initial values oF a and d are needed in case the statements Following the else statement are executed (these statements are a(k) = a(k-1) , d(k) = d(k-1) ). End-of-Chapter Problems 1. a) The pseudocode is: 1. Enter the range For r , aFter choosing an appropriate step size (here, a step size oF 0.01 m will give 301 values, enough to generate a smooth plot. r = [0:0.01:3]; 2. Code the Formulas For V and A . V = 4*pi*r.^3/3; A = 4*pi*r.^2; 4-4
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3. Plot the results. plot(A,V),xlabel( ± Area (m^2) ± ),ylabel( ± Volume (m^3) ± ) b) The program is: r = [0:0.01:3]; V = 4*pi*r.^3/3; A = 4*pi*r.^2; plot(A,V),xlabel( ± Area (m^2) ± ),ylabel( ± Volume (m^3) ± ) 2. a) The pseudocode is: 1. Prompt the user to enter the coefficients. Be sure to specify the format and the order in which they must be entered. disp( ± Enter the three coefficients in brackets (Highest power first).
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M7solns4 - Solutions to Problems in Chapter Four Test Your...

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