M7solns2 - Solutions to Problems in Chapter Two Test Your...

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Solutions to Problems in Chapter Two Test Your Understanding Problems T2.1-1 The session is ± B = [2,4,10,13;16,3,7,18;8,4,9,25;3,12,15,17]; ± A=[B;B ± ] ± A(5,3) A= 241013 16 3 7 18 84925 3 12 15 17 21683 43412 10 7 9 15 13 18 25 17 ans = 8 T2.1-2 a) The session is ± B = [2,4,10,13;16,3,7,18;8,4,9,25;3,12,15,17]; ± [x,k] = max(B); ± [maxB,column]=max(x) maxB = 25 column = 4 ± row=k(column) row = 3 b) Continue the above session as follows: ± C = sort(B) C= 23713 34917 841018 16 12 15 25 2-1
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T2.3-1 a) The session is ± A = [21,27;-18,8];B = [-7,-3;9,4]; ± A.*B ans = -147 -81 -162 32 ± A./B ans = -3 -9 -2 2 ± B.^3 ans = -343 -27 729 64 T2.4-1 The session is ± u = [6,-8,3]; w = [5,3,-4] ± u*w ± ans = -6 T2.4-2 The session is ± A = [7,4;-3,2;5,9];B = [1,8;7,6] ± A*B ans = 35 80 11 -12 68 94 2-2
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T2.4-3 The session is ± A = [6,-2;10,3];B = [9,8;-12,14] ± A*B ans = 78 20 54 122 ± B*A ans = 134 6 68 66 T2.5-1 The session is ± roots([1,13,52,6]) ans = -6.4406 + 2.9980i -6.4406 - 2.9980i -0.1189 ± poly(ans) ans = 1.0000 13.0000 52.0000 6.0000 T2.5-2 The session is ± p1 = [20,-7,5,10];p2 = [4,12,-3] ± conv(p1,p2) ans = 80 212 -124 121 105 -30 2-3
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T2.5-3 The session is ± p1 = [12,5,-2,3];p2 =[3,-7,4 ] ± [q,r] = deconv(p1,p2) q= 4.0000 11.0000 r= 0 0.0000 59.0000 -41.0000 T2.5-4 The session is ± p1 = [6,4,0,-5];p2 = [12,-7,3,9] ± ratio = polyval(p1,2)/polyval(p2,2) ratio = 0.7108 Using the deconv command, the session is ± p1 = [6,4,0,-5]; p2 = [12,-7,3,9] ± [q,r] = deconv(p1,p2); ± ratio = polyval(q,2)+polyval(r,2)/polyval(p2,2) ratio = 0.7108 T2.5-5 The session is ± x = [-7:0.01:1]; ± plot(x,polyval([1,13,52,6],x)),xlabel( ± x ± ),ylabel( ± y ± ) T2.6-1 Using cell indexing to create a 1 × 4 cell array, the script fle is: A { 1 } = [1:4]; A { 2 } = [0,9,2]; A { 3 } = [2:5]; A { 4 } = [6:8]; [x,y] = deal(A { 1:2 } ); B = [x,y] C=[A { 2 } ;A { 4 } ] [u,v] = deal(A { 2:3 } ); D = min([u,v]) 2-4
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T2.7-1 The script fle is student(1).name = ± John Smith ± ; student(1).SSN = ± 392-77-1786 ± ; student(1).email = ± [email protected] ± ; student(1).tests = [67,75,84]; student(2).name = ± Mary Jones ± ; student(2).SSN = ± 431-56-9832 ± ; student(2).email = ± [email protected] ± ; student(2).tests = [84,78,93]; student(3).name = ± Alfred E. Newman ± ; student(3).SSN = ± 555-12-3456 ± ; student(3).email = ± [email protected] ± ; student(3).tests = [55,45,58]; T2.7-2 The session is ± student(3).tests(2) = 53; T2.7-3 The session is ± new_student = rmfield(student, ± SSN ± ) End-of-Chapter Problems 1. a) Either x = [5:23/99:28] or x = linspace(5,28,100) will work. b) Either x = [2.:.2:14] or x=linspace(2,14,61) will work. c) Either x = [-2:1/7:5] or Either x = linspace(-2,5,50) will work. 2. a) Type logspace(1,3); b) Type logspace(1,3,20); 3. The session is ± x = linspace(0,10,6); ± A = [3*x;5*x-20] A= 0612182430 -20 -10 0 10 20 30 2-5
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4. Use the transpose operator. The session is ± x = linspace(0,10,6); ± A = [3*x;5*x-20] ± A= 0 -20 6 -10 12 0 18 10 24 20 30 30 5. The session is ± A = [3,7,-4,12;-5,9,10,2;6,13,8,11;15,5,4,1]; ± v = A(:,2); ± w = A(2,:); 6. The session is ± A = [3,7,-4,12;-5,9,10,2;6,13,8,11;15,5,4,1]; ± B = A(:,2:4); ± C = A(2:4,:); ± D = A(1:2,2:4); 7. The length is 3 for all three vectors. The following session computes the absolute values. ± x = [2,4,7]; ± length(x) ans = 3 ± abs(x) ans = 247 ± y=[2,-4,7]; ± abs(y) ans = ± z=[5+3i,-3+4i,2-7i]; ± abs(z) ans = 5.8310 5.0000 7.2801 2-6
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8. The session is ± A = [3,7,-4,12;-5,9,10,2;6,13,8,11;15,5,4,1]; ± min(A) ans = -5 5 -4 1 ± max(A) ans = 15 13 10 12 ± min(A ± ) ans = -4 -5 6 1 ± max(A ± ) ans = 12 10 13 15 9. The session is ± A = [3,7,-4,12;-5,9,10,2;6,13,8,11;15,5,4,1]; ± B = sort(A) B= -5 5 -4 1 3742 69811 15 13 10 12 ± C = [sort(A ± )] ± C= -4 3 7 12 -5 2 9 10 681113 14515 ± D = sum(A) D= 19 34 18 26 ± E = sum(A ± ) E= 18 16 38 25 2-7
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10. a) The session is ± A = [1,4,2;2,4,100;7,9,7;3,pi,42]; ± B = log(A) ± B(2,:) The answers are 0.6931, 1.3863, and 4.6052.
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This note was uploaded on 04/02/2008 for the course ENGINEERIN 127 taught by Professor Finch during the Spring '08 term at Rutgers.

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M7solns2 - Solutions to Problems in Chapter Two Test Your...

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