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Physics 132 Experiment 11

# Physics 132 Experiment 11 - Phys 132 Experiment 11...

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Phys. 132 Experiment 11: Vibrating Strings Part 1: Calculations: Equations: Units: Y = mx + b m (Slope) = 8.3585 N/m F = kx k = F/x m = F/x k = 8.3585 F(N) = k N/m * x m K N/m = F N / x m m N/m = F N / x m k = 8.3585 N/m Therefore, according to the static determination of k, the approximate spring constant for this spring is 8.354 N/m. Part 2: Calculations: Equations: Units: Y = mx + b m (Slope) = 4.702 s 2 /Kg

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2 = (4π 2 )/k * m + (4π 2 )/k * fm s m (Slope) = (4π 2 )/k k = (4π 2 )/m k = (4π 2 )/4.702 k = 8.396 T 2 s 2 = (4π 2 )/k * m NKg/m + (4π 2 )/k * fm s NKg/m m s 2 /Kg = (4π 2 )/k N/m k N/m = ((4π 2 )/m) Kg/s 2 k N/m = ((4π 2 )/ 4.702 m) s 2 *m/Kg*m k = 8.396 N/m Therefore, according to the dynamic measurement of k, the approximate spring constant for this spring is 8.396 N/m. Percent Difference: Percent Difference = |8.3585-8.396| / 8.3585 * 100 Percent Difference = .004 * 100 Percent Difference = .4% Therefore, the percent difference between the values of the two different ks is .4%.
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Physics 132 Experiment 11 - Phys 132 Experiment 11...

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