Chap6 Section2

# Elementary and Intermediate Algebra: Graphs & Models (3rd Edition)

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Section 6.2 Zeros of Polynomials 577 Version: Fall 2007 6.2 Exercises In Exercises 1 - 6 , use direct substitu- tion to show that the given value is a zero of the given polynomial. 1. p ( x ) = x 3 3 x 2 13 x + 15 , x = 3 2. p ( x ) = x 3 2 x 2 13 x 10 , x = 2 3. p ( x ) = x 4 x 3 12 x 2 , x = 4 4. p ( x ) = x 4 2 x 3 3 x 2 , x = 1 5. p ( x ) = x 4 + x 2 20 , x = 2 6. p ( x ) = x 4 + x 3 19 x 2 + 11 x + 30 , x = 1 In Exercises 7 - 28 , identify all of the zeros of the given polynomial without the aid of a calculator. Use an alge- braic technique and show all work (fac- tor when necessary) needed to obtain the zeros. 7. p ( x ) = ( x 2)( x + 4)( x 5) 8. p ( x ) = ( x 1)( x 3)( x + 8) 9. p ( x ) = 2( x 3)( x + 4)( x 2) 10. p ( x ) = 3( x + 1)( x 1)( x 8) 11. p ( x ) = x ( x 3)(2 x + 1) 12. p ( x ) = 3 x ( x + 5)(3 x 2) 13. p ( x ) = 2( x + 3)(3 x 5)(2 x + 1) 14. p ( x ) = 3( x 2)(2 x + 5)(3 x 4) 15. p ( x ) = 3 x 3 + 5 x 2 12 x 20 Copyrighted material. See: 1 16. p ( x ) = 3 x 3 + x 2 12 x 4 17. p ( x ) = 2 x 3 + 5 x 2 2 x 5 18. p ( x ) = 2 x 3 5 x 2 18 x + 45 19. p (

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