GC_4253_L08_Gas_Laws.docx - Gas Laws PRE-LAB QUESTIONS 1 What is the conversion from Celsius to Kelvin and why is this conversion useful when applying

# GC_4253_L08_Gas_Laws.docx - Gas Laws PRE-LAB QUESTIONS 1...

• 8

This preview shows page 1 - 4 out of 8 pages.

PRE-LAB QUESTIONS 1. What is the conversion from Celsius to Kelvin and why is this conversion useful when applying gas law calculations? The conversion is adding 273 K to the temperature in Celsius. This is useful because Kelvin is a concept of zero heat energy that we use during ideal gas law equations 2. A room is heated from 15 °C to 30 °C. What are these temperatures in Kelvin? 15 degrees C +273K= 288K 30 degrees C +273K= 303K 3. Following question 2, what is the temperature change in Celsius? What is the temperature change in Kelvin? The change in Celsius is 15 degrees and the change in Kelvin is 15k. They are the same. 4. What is the barometric pressure in your region? If necessary, convert from mm Hg to atmospheres (atm). Divide the measured pressure by 760 mm Hg. This will give you pressure, (P), in atmospheres. The barometric pressure is 1 5. Convert a volume of 564.3 mL of oxygen from mL to liters (L). 564.3ml equals 0.5643 L Gas Laws
6. Rearrange the ideal gas law (PV = nRT) to algebraically solve for n, using the values you calculated above at a temperature of 30 °C. P=1 atm, V= 0.5643L, R=0.821, T= 303K N=(1)(0.5643)/(0.0821)(303) N=0.0227 mol Gas Laws
EXPERIMENT 1: IDEAL GAS LAW – FINDING PERCENT H 2 O 2 Data Sheet Table 1: Temperature, Pressure, and Volume Data Temperature of Distilled H 2 O: Room (or regional) Pressure (atm): Initial Volume of Air (mL) Final Volume of Air (after reaction) (mL) Volume of O 2 Collected (Final Volume - Initial Volume) 20c 1.0076 5ml 48 43 Table 2: Reaction Time Data Time Reaction Started Time Reaction Ended Total Reaction Time 20:32 20:32:54 0:54 Post-Lab Questions 1.

#### You've reached the end of your free preview.

Want to read all 8 pages?

• Spring '15
• Khurana

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern

Stuck? We have tutors online 24/7 who can help you get unstuck.
Ask Expert Tutors You can ask You can ask You can ask (will expire )
Answers in as fast as 15 minutes
Ask Expert Tutors