GC_4253_L09_Enthalpy_Specific_Heat updated.docx - Enthalpy and Specific Heat PRE-LAB QUESTIONS 1 When 3.0 kg of water is warmed from 10 °C to 80 °C

# GC_4253_L09_Enthalpy_Specific_Heat updated.docx - Enthalpy...

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PRE-LAB QUESTIONS 1. When 3.0 kg of water is warmed from 10 °C to 80 °C, how much heat energy is needed? q=mc∆T C of water is 4.187 q=(3000)(4.187)(70)=879,270 joules 2. A calorimeter contains 100 g of water at 39.8 ºC. A 8.23 g object at 50 ºC is placed inside the calorimeter. When equilibrium has been reached, the new temperature of the water and metal object is 40 ºC. What type of metal is the object made from? Qcal=Qmetal Qcal=q=mc∆T=100g(4.187)(0.2)=83.74 C=Qmetal/m∆T=83.74/(10)(8.23)=1.0174 C of magnesium is 1.02 3. Enthalpy and Specific Heat
EXPERIMENT 1: DETERMINATION OF SPECIFIC HEAT OF A METAL Data Sheet Table 2: Mass Mass (g) Water 50.2 Unknown Metal Strip 18.2 Table 3: Specific Heat Data Time (minutes) Temperature (°C) Trial 1 Trial 2 Trial 3 Initial 25.3 25.8 25.7 5 minutes 25 25.6 25.5 6 minutes 24.8 25.5 25.5 7 minutes 24.7 25.3 25.3 8 minutes 24.7 25.2 25.3 9 minutes 24.5 25.2 25.3 10 minutes 24.4 25.2 25.3 Average Specific Heat Capacity of the Unknown Metal: Trail 1=11.546 Trail 2=11.546 Trail3=11.545 Average is 11.54566 J/g deg C Post-Lab Questions Enthalpy and Specific Heat
1. Why is ΔT metal < 0? Because temp in the metal is greater than the temp of the water 4. Why is ΔT water > 0 ? The water starts out at a lower temp than the metal the temperature wants to stabilize at a temperature between them 5. A metal sample weighing 43.5 g and at a temperature of 100.0 °C was placed in 39.9 g

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