ExampleFinal3.pdf - MAE 251 – Structure and Analysis of...

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Dr. Olivia A. GraeveMAE 251 – Structure and Analysis of SolidsFinal Examination SolutionsThe two crystal structures shown below correspond to ZnO and In.For the case of ZnO, the space is P63mc and the lattice parameters area= 0.335 nm andc= 0.522 nm.Thecrystal on the left shows the bonding in this material and the crystal on the right shows the atoms within theunit cell.In the structure, the Zn ions are in contact with the O ions.It is known that Zn ions have a radius of0.74 Å when tetrahedrally coordinated and 0.89 Å when octahedrally coordinated.The atom positions are:Two Zn ions at13,23, 0and23,13,12Two O ions at13,23,38and23,13,78For the case of In, the space group is I4/mmm and the lattice parameters area= 0.4598 nm andc= 0.4947nm.The In atoms are in contact along the body diagonal.AZn= 65.38 g/molAO= 16.00 g/molAIn= 114.82 g/mol
1.Determine:(a)the distance between Zn and O ions in ZnO,(3 points)
(b)the radius of the O ions in ZnO,(3 points)
(c)the radius of the atoms in the In crystal,(3 points)
(d)the atomic packing factor of the In crystal.(6 points)
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2.Calculate the atomic packing factor and the density of ZnO.Based on the APF value you find, what type ofbonding is predominant in this material?
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Dr. Olivia A. GraevePage43.Indium is in column 13 of the periodic table, below boron, aluminum, and gallium.

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Term
Fall
Professor
Olivia
Tags
Diffraction, Dr Olivia A Graeve

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