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Unformatted text preview: (c) mean equal to 1.99 lb. and standard deviation of 0.04 lb. (d) mean equal to 1.99 lb. and standard deviation of 0.01lb. ____3. The probability that a random variable having the t distribution with 4 degrees of freedom is greater than t 0.025 equals. (a) 0.025 (b) 0.975 (c) 0.05 (d) 0.95 ____ 4. Find t such that P(T 3 > t) = 0.05. Here T 3 denotes a random variable with the"t" p.d.f. and ν =3 . COMMON INFORMATION 57. Y k ~N(1,16) for k=1,2…25. The Y j are all pairwiseindependent. That is Cov(Y k , Y t )=0 for all k and t; μ Y =1, σ 2 y =16,n y =25 and let 25 25 1 ∑ = = k k Y Y . Let S 2 Y = 24 ) ( 2 25 1 ∑ =k k Y Y . 5. Mean value of S 2 Y ( ANS. 16) 6.. Standard Error of Y 7. Pr( Y < 0) = Φ ( Z ) ; Z=_?____ ANS: 1. B 2. A 3. B 4. 2.353 5. 16 6. 0.8 7. 1.25 1...
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This homework help was uploaded on 01/31/2008 for the course AMS 310.01 taught by Professor Mendell during the Fall '03 term at SUNY Stony Brook.
 Fall '03
 Mendell

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