practice quiz 7 and soln - Prequiz 7 PRACTICE QUESTIONS FOR...

Info icon This preview shows page 1. Sign up to view the full content.

Prequiz 7. PRACTICE QUESTIONS FOR QUIZ TODAY . NOVEMBER 2, 2003 1-2 A box of “1 lb.” weights must have a mean weight of 1 lb. with a standard deviation of 0.04 lb. _____1. We take a sample of n=100 weights and calculate the average of these. We let X denote the average of a sample of 100 "1 lb weights". Which statement is true of the distribution of X ? (a) mean equal to 1.0 lb. and standard deviation of 0.04 lb. (b) mean equal to 1.0 lb. and standard deviation of 0.01 lb. (c) mean equal to 1.99 lb. and standard deviation of 0.04 lb. (d) mean equal to 1.99 lb. and standard deviation of 0.01lb. _____ 2. We take a 1 lb. weight at random and X, denotes its weight. Which statement is true about the distribution of X? (a) mean equal to 1.0 lb. and standard deviation of 0.04 lb. (b) mean equal to 1.0 lb. and standard deviation of 0.01 lb.
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (c) mean equal to 1.99 lb. and standard deviation of 0.04 lb. (d) mean equal to 1.99 lb. and standard deviation of 0.01lb. ____3. The probability that a random variable having the t distribution with 4 degrees of freedom is greater than -t 0.025 equals. (a) 0.025 (b) 0.975 (c) 0.05 (d) 0.95 ____ 4. Find t such that P(T 3 > t) = 0.05. Here T 3 denotes a random variable with the"t" p.d.f. and ν =3 . COMMON INFORMATION 5-7. Y k ~N(1,16) for k=1,2…25. The Y j are all pairwiseindependent. That is Cov(Y k , Y t )=0 for all k and t; μ Y =1, σ 2 y =16,n y =25 and let 25 25 1 ∑ = = k k Y Y . Let S 2 Y = 24 ) ( 2 25 1 ∑ =-k k Y Y . 5. Mean value of S 2 Y ( ANS. 16) 6.. Standard Error of Y 7. Pr( Y < 0) = Φ ( Z ) ; Z=_?____ ANS: 1. B 2. A 3. B 4. 2.353 5. 16 6. 0.8 7. -1.25 1...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern