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Unformatted text preview: Quiz 6 October 27 Print your name here: ___________________________ ID #__________ (use all UPPER CASE letters) ______1. Suppose that X has mean =2 and =1 and Y= 3 2X. The standard deviation of Y equals_____ _____2. Suppose that X 1 and X 2 have mean =5 and 2 = 4 and Cov(X j , X k ) =0 for j k . Then the variance of Y= X 1 X 2 equals_______ 34. Suppose we take a random sample of n=4 values of X. We let X 1 denote the first value in the sample, X 2 denote the second value, X 3 denote the 3 rd value and X 4 denote the 4 th value. Given (1) 1 = 2 = 3 = 4 = x = 8 and (2) 1 = 2 = 3 = 4 = 2 x =10. Let 4 4 1 = = i i X X . Because each of the Xj are random variables, X is a random variable. _______ 3. The mean value of X equals____ ________ 4. If the population size, N>> 4 then Cov(X j , X k ) = 0 for all j k and the X j are independent, so Var( X ) = ____ 1 SOLUTIONS TO QUIZ 6 ___ 2 ___ 1. Suppose that X has mean =1 and =1 and Y= 3 2X. The standard =1 and Y= 3 2X....
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This homework help was uploaded on 01/31/2008 for the course AMS 310.01 taught by Professor Mendell during the Fall '03 term at SUNY Stony Brook.
 Fall '03
 Mendell

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