Lec_05 - 72V J51%.: SL5 + big; +8313 — {ac} =5 05:815....

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Unformatted text preview: 72V J51%.: SL5 + big; +8313 — {ac} =5 05:815. GA. LI 4-bit} _L5=fl (if =ZA —- Kai-"'2 (£430 "* .= “m = ((9130.29): 3&DCL3 .q KCL : KVLZ 4'; ‘ do lk+§E _ U; -_-. (5mm :Sov .oouso) + L. +¢¢ =0 2mg == SOOLO i0 = 45...] "GO‘MA —JHOMA ________W~T________._____ uuuuuuuuu h _"__._—--- I .. u we: "E. a. ._ any-H.511. R: 144-2.sz573 ‘pmflflnfl 3. G Ignaz"! . Din-OW l1 .0 5%‘52 _______ ___| . LL‘I'IO ?#E=%'mu 3mm Elk = min-sun +12: :ZQ.3_S_1j[£L- 0.. 24.354”; p: D’L» mm b (“I L = Ind/24.554: = 5.‘E:z7¢,A *p = (mqumzm) = 851.4576: LU Mallard EE ED! Spring EEG} MWF Milli} v Homework: H.451 Pair: 1 of ] % Homewnrk: M.4.51 Yuu may submit this Humcwurk :- Lntal of In times and rccc'tw full crucill. Eigfl__l:__umui_m_i~.:g_ gjglflpluliinn mums This is similar [4:1 pruhlum 2.22 in mu" text Thu qrmflr'fln I'S ddupidr'i'. WEI-"I pumiflfartfmm IJ'JE puhfiflzer:_fi"flm probic'm 4.5} uj'rmr rmrbnok, Ersatz-ir- Chm-I'm. Nn'smrr and Rig-dc}. 5H.- L'fl'l'fl'on. rida'fSWJ-Wt'fl'fly. I996: if a'rfnfmdcdfnrusfl Jay Fc'g'llfil'cf't‘d s'riuic'rtrs arias-ca .S'mre Unircr.u':_r andm:1_1.'nfl! Ear: Itmdjm whar- purpasw wz'IImm Hm awraj'sed pr:rmi.-.'.-rr'0n of #1:.- puhfiflzer. Us: a series of snurce Uansformatiuns to find mu turrunL in in the circuit hclnw. R] = 1.3 kiln—nhms R2 = 2.? kilo-ohms R3 = Li] kilo—ohms Ii = 3 milliampnres I: = 2 milliamperes . Find L1“: 1:01ng of I11: suurcc Iransfnrmed from II. Tim valmge is defined m be pasz'rfsre r'frhe clean-n" pmenn‘ui a: Hat Mp affix 1'5 gruare'r n'rrm rim pure-min! a: file bmmm :5er I _ vults. 2. Find the vuitflgfl [If the source transformed frfim 12. NHL? mirage if defined In beposfrr're [film gfglca'ric-pmgnriu! a: mg mp off-33 1'5 greener man the parerm'm‘ ar the bottom afflj. I vnlts. 3. Fin-.1 the value ofifl. I _ umpcrcs. El Sul;i11[t"fi:jr arming" .jh. Mallard CrJ Ti .72! :3 ififlj-Effl'm Cnuri‘e Mam-m} Capyn'gh: ID 1993 - 2W5 fawn Erma Unit-c r5in hupsflmce—unlinc .ccjaalattcdufEEEDI 513133 mwf 1 wacbquiz.cgi?5 csaionm=kmempeLl 133 . __ 1 EMEUIIJS { I Pméa m m gew'as «'wa ZGL _ in - . _______T_._______.___________ ____ _, Volga eiDN'lOlQ‘D mm] \ocm‘ 3mm W‘me E. MARL- Pz’ =_ QL-‘E'z. ‘RLfi-‘RZ. a. I l% , + DEB-10‘s R2- UE: E; 4' -‘R‘ _____ __MWT__________¢W#W CurrewL {AE‘C‘ . ‘ WLZ. + _._.*W—_m_—__~Wmmmmmmm_mm Source Transformations as a _ 3 VS : [SE (a) b (b) b Hp Rs vs R5 is II the rest of the circuit can't tell the .difference it is deed to "reduce" a circuit “source transformation" does not preserve source power -.-.-..—-.-.-—. WM—mmm__ Rom EXCEM‘P’Q. 2-6, p.57 250V 8A to 29 t 25 I25 —‘7"® Ibo IOO m [‘59- GOV m DHILL EXERCISE 2.4 in} Us: u SEE‘iEfiS Di" wuz'cc Lranal'mrmmiuns Lo Hm] the voltage a: in tha- uircuil slum-n, {b} How much powur aim-:5 1h: 11’] ‘v' SLILH'LLr: LIL" liver to [ht‘ circuéL? ...
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Lec_05 - 72V J51%.: SL5 + big; +8313 — {ac} =5 05:815....

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