Lec 14 - 3.110 b) Spam citsQPQM “PM = {50%;} ~=~ zsoto...

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Unformatted text preview: 3.110 b) Spam citsQPQM “PM = {50%;} ~=~ zsoto Fla-z. -= (~5)Z'2_ -= Soul) FR 420914 = mam P,5 =(lmz-6 = [280 L0 Pu: =LDZ-ZO -'= 20 “’3 +o+¢Q&<s¢\PaM 33w Lo ' szmol—Lscc m .. WWM W PT“ 3 “sq/ALL 2 205,—.- CL Q 2052.. 2052— ‘Islw ‘0 42A .0 Mallard EE EDI Fall EDDIE ma: lflflfl — Homework: M.4.65 Page 1 of 1 Homework: M.4.63 E You may submit this Homework a total of in times and receive full eretlit. V1if:ELEMIJluJ.eii.‘:rE_!ZEEUifl£[LQ11 Status This is similar to problem 3.53 in our text This {EEIL'JTJ'I'JH 1's maimed. with pemu'ssr'oufiom the publisher. fiom Itire-hirer: 4.53 qfoiir' textbook. Bic-erri'e Ci'i'ei-rirs. Ni'Lrss-h and Hie-rial .irit edition. :tdii'ison-lri’esiey. I996: it is i'mencfedfor use by registered siuiierirs err films .S'reite Ll'iir'vers-ir'i- and may. not he rue-cilihr miter ourposes ii'iti'mm' the expressed permission of rite pitiih'si'ier. Determine the Tltet'enin equivalent with respect [L'I the terminals a—h for the single stage. common emitter amplifier circuit whet-ti: small signal equivalent circuit is Shuwn below. R1 = 10D ohms. R2 = 93E: ohms. and R3 = 4D kilo-rith. I5 = 537 microumperes . Finr] the 1salute of Use Thevei'iin voltage, V-[h = at the terminals a-h fish, 1:2 when a-h. are open :it'euited. l volts. ‘3. Find the value of the short circuit current. iSE . first will flow downward enough the short when terminal a is sherhed LtI terminal h. |_ _ miiiiamperes. 3. Find the vaiue of the ThBVEnili resistance. R-m . when looking into the network from the terminals-r ah I __ __ __ ohms. Sufit-‘ell'icitZ-‘Etéflitlaz 15: Meth'urt.’ Carp-right '3' . Course Material Copy-rigth [993 r 205'! {mm State University hrtpsLHeee—onlineee.iastaieedw'EEZfli iflflmwf1Elia-sheuiz.ogi?SessiortLD=kruempei_lDEG... SUE WEDGE U:RP5piCE PrujectsREE EGlHn 4 12Rnilseen fi—SCEEHATICl—Nilsean 4.12 by Ken Kruempel.eut “1" DEEZSIDI UT:41:4? '*'******" Evaluation PSpice [max 1999: ****’********’ ** circuit file for prefile: Nileeen 4.12 by Ken Kruampel T*‘* CIRCUIT DESCRIPTION *TwItriit*1*ifi?*ttt*ktrtrtriiwirfl1111flifllilviiwtububeqtiei+i++bfi*'*+***+****g *' WARNING: THIS AUTDMATICALLY GENERATED FILE MAY BE GVERHHITTEN BY EUESEQUEHT PROFILES “Libraries: * Lezal Libraries * From {PSPICE NETLIST] section of pspiceev.ini file: .lih nem.lih *Analysie directives: .DPTIUHE NGPAGE .PRDEE .INC 'nilfisnn fl—ECHEHATIC1.net‘ ’*'* INCLUDING 'niiseen d-SCHEHATIEl.net“ **** 7 source NILSSDN 4 v_v1 NDflUlH fl 3UVflc R_fil NDflDlfl NDEUZS 15 R_R2 NUUUZE NDfiUEE 25 R_R3 U NDDHEE 5D L54 :1 NUL‘IGHE 31.25 R_EE NDUUEE NDGUEE 5D I_:1 NDGDE3 NDUUEE DC lAfi: 73.2 mama mamas m: we: *“‘ RESUMING 'nileeen 4—SCHEMATICl—Nilesnn 4.12 by Ken K:uempel.5im.eir“ **** .INC "nilssnn d-SCHEMATIC1.a15" *"* INCLUDING 'nilssan fi-ECHEMATIC1.315' **** .ALIASES '-..r_1.ri Vlli'—=NI:ID{+19 —=0 3 R_R1 Rldlzyflfifllfi flzmfiflDES R_R2 RE#1=NUDGZS 2=NDUDEB F._F.3 R3-::L=D 2:1«2110053 J R_R4 Rd§1=D zzunanzs J R_RE R541=NUDG63 2=NDUD23 I_;1 Il¢+=mflfifl63 —=NDUD28 1_12 T2<+2NGDEEB -=nfiflfl25 .ENDALEASES ‘*" RESUMING 'nilssen 4—SCHEMATICl—Nilssne 4.12 by Ken Kruempel.5im.:ir' ***' .END '*‘* SHELL SIGNAL BIAS EDLUTIDN TEMPERATURE = 27.DUD DEG NUDE UBLTAGE NUDE VOLTAGE NUDE VOLTAGE NUDE VOLT GE iNUGUlE] lfl.flUGG {NUUDZE} 35.nflflfl [NHDUES1 -£E.UUUU iHUDUEEI —GE.UGUE l Thevenin and Norton E uivalents 6L Q. 03m Ln “Rn b b Thevenin voltage: vfi = open circuit voltage Norton current: in = short circuit current Equivalent resistance: 'Rul = Rn Vth = Rm in To find the Thevenin voltage or the Norton current, you can use: ‘ node voltage method mesh current method source transformations (for independent sources) - W Thevenin and Norton Eguivalents Finding the Thevenin or Norton Resistance: 1. "Deactivate" the indeQendent sources voltage source : 0 volts = "short" current source 0 amps = "open" 2. With degendent sources, after you deactivate the independent sources, apply a test voltage or test current at the terminals: Pa = Rn = mast) I owe) In most cases, you can set one voltage or current in the "test" circuit to a "convenient" value and then find vtest and itest ‘50 2 OF 3 $41893 0. Open Qt'rcult'l' \Jo Hit-fie. Call sources) 2.),Shor+ cirwfl curmud- («u sources) 35. 135* Volhge/HmF currewd' , Rt“ (awwak) Lyssa, Hm S-Feps 'm qomv 30‘ 1.93—th 1 ’ 0-93“ CL'PLLLE'I' . ShorJr Circui‘i- Cuvrew+ , Téfi— vol-kacce/car new} 3.19 Find the Thévenin equivalent circuit with respect to _ the terminals tab for the circuit shown. 12!). Dead-tirade. 7ZU Source— 3 a. Qasz. 3.22 Find the Thévenin equivalent circuit with respect to the terminals a,b for the circuit shown. 3i. o WWW—m———rm Dbl \L" :1 o . Ln. Mm . ...
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This note was uploaded on 04/02/2008 for the course EE 201 taught by Professor Kruempel during the Fall '06 term at Iowa State.

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Lec 14 - 3.110 b) Spam citsQPQM “PM = {50%;} ~=~ zsoto...

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