Lec 15 - Thevenin and Norton Eguivalents Finding the...

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Unformatted text preview: Thevenin and Norton Eguivalents Finding the Thevenin or Norton Resistance: 1. "Deactivate" the indeEendent sources voltage source : 0 volts 2 "short" current source 0 amps = "open" 2. With degendent sources, after you deactivate the independent sources, apply a test voltage or test current at the terminals: Rth 3 Ru 2 (fitest) / (itest) In most cases, you can set one voltage or current in the "test" circuit to a "convenient" value and then find vtestandit39¢ c)me amt vow» .. -'5 ' Lb: b1=-'Lfb(40'bbh 103:2: 0-2. = *QSQZU 1 La: —40(:b Lb: 58.7114 in (3-2— :G [cm is; : I14 M A Him n G- hq l ‘qlu 12m = 3 0‘1 : Lia'sz 3 ~11qu lea; Lyfimew mV ~ —'5 1983 bB‘x‘: ‘ +1.93: A ’40“: [mg 25mg“ 'R :b‘we’r‘ TH /Lk9+= 199—;— zamaufi = L13IZ.C:G 1.2- Mallard EE 2i]! Spring 21303 MW]: mm — Homework: MARI Page I of: E Homework: M.4.71 You may submit this Homework :1 tom] of [U Limes and receive full orediL. 1«Fist-r eumuIaLix-‘e enm ietinn status This is similar to problem 3153 in OUT Lest This question LT adopted. with pennifiiwifi'om the publisher. fires: problem 4!. FE nfaur ieuboek, Eieen'ic Circuits. Misses out! Ri'edei. fill edition. Addison-Wesley, I996: ft is intendedfor use by registered “infants or fawn State University and may not its meti'for other pita-poses without the CAPTEJFIL'I! permission of [he pubi'fs'hcr. Given that: v3 = see 1colts, R2 = lflfl ohms. R3 =1fl ohms. and i11 =ss *1: in the circuit below. R1 = 24 ohms. 114 e If: ohms. The variable resistor. in the circuit above is adjusted until power dissipated in the resistor is 250 watts. Two values of RC| are found. The solution Stratum-for this problem Ltfi'rsr mfind the Thevenfn equix'ai'enr circuit Hear the variable food resistor sees making bad: inn: rm: circuit. Ham to write the mothenmtierxi expressinnfor the power dissipated in the varmwe Road resistor m afimcrimr raffle set this equal to 2‘50 Watts and solve:on R0. Note that the mathematical solution wi'ii' involve monotone numbers that are offlie same order ofrrmnnimde. Therefore to get your mum-er m be within the 2% limit alianed deviation. you may need to carry settemi' s'fgny'imntfigm'es aiming in you compurotfons. 1. Find the Thevenin. open circuit voltage as seen by the variable iond resistor, RCl {with peisrity e on top GER“ and - on the hetiem of Ru} . I _ _ _ _ volLs. 1. Find the larger value of Ru . htips:Heee—oniine.ee.isstate.edw'EE2fl1spfl3mwf]{Illi'webquizegi?SessionLD=It_ruempe]_142:3... 2f 1 "H2 [303 Mallard BE 20] Spring 2:333 MWF lflfll] - Homework: MAJ] Page 2 of 2 l _ _ __ uhms. 3. Flncl the value e1" veltuge across the larger value ef Ru . l _ _ _ _ _vells. 4. Find the smaller value uf RU . _ ___ __ _ ___ uhms. 5. Find the value ui' Unltage HEIDI-15 the smaller value of RB . _ l wills. e'uemitjfdrfifefiiefi" ' % .uauumcegm-zlelreeeeeeeee Chums Material Cupyfigh! :3] I993 - 29133 Iowa Siam Um'vgrfllj.‘ httpszfle ce—enlt11e.ee.iesrate.edwEE2fl 1 513133 mwf l flfwebquiz.egi?5eesienlD=kruempel_ l 133. .. 2.} 1 W2 CID} MAN MUM fipcmea T‘EAN%F6E . “0+ 6% (cm 0&1 mermsgzn :- S‘hfl‘ ¥mm¢ mmm ecbW MM.IMQWK $9M}. ETEL. 3.24 (:1) Find the value of R that enabies the circuit shown to deliver maximum power to the termi~ nals a,b.. (b) Find the maximum power delivered to R. USA-Digs 7/“: ..... ___#—-mfl—W_m—— 3.le 0% Wm} \Joljggg Volstaqq $0M: 0?; =00 Nada—l1 U] -0; (51-20 b1_(U;+_U'¢) ---—- 'i' ——-—--'l" __________.._.__.._._-:: H L!- E: %.\}Q3\1h&b&21 bagS—Tmfizo .______m,.._......—._.__...__..——«—————-— .W_—__mn—u_—___W—__—m_w.__.__.n—— T854 VGH‘CLQSL/ 445$ Qmw. 3.25 Assume that the circuit in Drill Exercise 3.24 is de— Iivering maximum power to the load resistor R. (a) How much power is the 100 V source deliver- ing to the network? (b) Repeat (a) for the dependent voltage source. (c) What percentage of the total power generated by these two sources is delivered to the load resistor R? ...
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Lec 15 - Thevenin and Norton Eguivalents Finding the...

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