This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Mallard EB 2131 Spring RUDE MWF lﬂtﬂﬂ — Hmneworlt: M.L.1 Page 1 of 3’. % Homework: M.L.1 You may submit this. Hemewar}: a total of ID times and receive full credit. :I' Emmulnn‘iejnmnletionﬂslus lndueinr VoltA. mpere Relationship Consider an inductor with inductance. L. where tth} is the current through the Inductor and tht} is the voltage across the
inductor. [The polarity of tht} is chosen eensistnnt with the passive sign ennvenlinnJ Assume.
iLit} = {J A for t 5 [I‘
and
iLitJ = os ti 4“ in fortgﬂ‘ 1. Which iiiiinfl of this following statements are me C" I— The voltagesLin. will start at zero. loll gradually to some negative value. then increase again In new.
l“ The voltage.vL{t}. will relish some positive. constant value tiller :1 long time. I— The velmge.tLt'tl. will Stan at zero. rise gradually to some positive value. then decrease again to zern
[— The voltagesLit), will start at vero. jump to some positive value. then decrease agree to zero. '— Tne veltagc.t'L{t:I. will start HI ztm. jump in some negative value. then increase again to zero. ’— Tth FUIULEEJLHL stays zero for all L '— Nune of muse.
l‘." The Fﬂllﬂgcﬁ'Lﬂ}, will reach 3mm: negative, constant value after u long time. r. The whitenrim. is zero before t = ﬂ 2. H L = 5 H. whet is the value of the voltage, vL. across the inductor at t = 1 sec “l I _ volts. 3. Given the some itirluetot'1 assume :
slit} 2 I] volts for t 5 C". ith} = ﬂ amperes for t 5 ﬂ‘ and
thijzrt E'ﬂﬁVI—mlzﬂ—F Which [if any] of the following statemean are true ? F The CIJITBIHT. ﬂu'ntigh the inﬂuetm', 5L. will reach some negative. constant value after :1 long time.
1— The current through the inductor. iL. will start at zero. jump to some negative value. then increase again to zero. T 111: current through the inductor. iL. stays zero for all t. https:ﬂeceonlitieeejastateedufEElﬂl spﬂﬁmwfl ﬂfwehquiz.egi'lSessionID=hme1npel_ l 13311}... 3G}? DU} Mallard HE 201 Spring EGGS MWF lﬂﬂ}  Homework: M.L.I Page 2 hf 2 '— Thr. urnmm through Ihc inductor, iL. is 2mm ht:me t= [1
IT The current through Ih: inducmr. iL, wiil sun at ram.ij to same positive: valur; than dame. again tn ZBIIJ. '— The current Ihraugh Illa induatﬂr. it Will start 31 mm. I'nﬂ gradually In sum: negative ulna. then increase again
tr: 2cm.
1— Nnn: of than. 1— The current thrrmgh the inductor. iL.wi]1rear:h mm: puritive. cnnstant value after a long time. [— Thr: currunt Ihmugh lh'l': inductor. :iL. wiil stun at zero. rial: gradually tr: 5mm: puritivc vuluc. than decrease again
to zero A. chc value 01' th: inductance. is 11 mH. and ivat't‘t is :15 in the. nhmrc pmhlrrrr.ﬂ1un what is the entrant thrnugh 1hr:
inductm ntt = I 5:: '.' 1 _ mpcrcs. Mammumwm
Cutrm Marathi C'ﬂpyn'ght (5 I993  3393 Innw Starr Untrﬂn'ly https:ffecr:4m]inc.cc.ia5tatﬁ.cdufEEEDlspﬂ3m wt I 17hr wehq trim: gi Hes siunID=krucmch1 DEG... SISIEUGE Mallard EE 2131 Spring 21113 W mm v Humwurk: MEJ Page E 0f 2 E Th: vulmgn across Ihr. capacitm. vcﬂl. will reﬂh some nzgat'w: constant value after :1 long time.
[— Hunt: of Elms: choices. '— Thr: vallagu across the capacitor. vim. will mh sum: pusitivc constant value after a iung mm. 4. If the value of the capacitor is 31 micrufarads. and il‘ ictt} is lha: Sam: as in qucsﬁnu 3 abm'c. ﬁnd me wimg: across the ca acitur at t = 9 mantis.
I _ m:gavnlts. T Iiiiéi'fﬁﬂﬁzﬁﬂlnl h Mmfnniﬁfpw'rmli Q. IEMJL'W
Emir” MEIERﬂ: fppyrigh: C‘ 3993  3093 Iowa 5:51: ﬁrthruff} https:ffeceunnIinc.cc.ia£taIc.edu!EEEU ] spﬂﬁm wf I '3! w chq uiz.c gi?5:ssinn[ﬂ=kmem p:l_ I (ED. . . 3f3f20ﬂ3 Mallard EE Elli Spring 2W3 MW}: lﬂtﬂﬂ — Homework: M.Cl Page 1 of 2 % Homework: M.C.1 % You may submit this Homework 3. total of illl times and reeoi'lre Full credit.
Eiraecuutulatieeeomuleauutatus Capacitor VoltrAmpere Relatlomltlp Consider a capacitor with capacitance. C. where tElt) is the voltage across the capacitor. and icltt is the current through the
capacitor. {The polarin of tic{t} is chosen consistent with the passive sign convention.) Assume .'
ticll} = U '5’. fort 1: il' seconds and edit = l  e'ﬂ trolls for l .1 W”.
l. Which. ll arty. of the following statements are true 1’ l The current. tctt}. is zero heloret = El. l— Hone of these. l— Tl'tc current. iclt}. will reach Some negative constant 1.11er after along time. l— The current. iclt}. will start at roteJump to some positive 1taluc. then decrease to teem. l— ‘I‘lte current. ictt}. will start at rero. gradually rise to some positive value. then decrease again to zero.
'— ‘t'lte current. iclt]. will result some positive constant value after a long time. F 'I‘]'te cun‘ent. ictt}. will start at euro. jump to some negause value. then increase to zero. r The current. iclt}. stays zero [or all L '— Tho currem, iii{t}. will start at zero. gradually.r fall to some negative value. then increasu again to zero. 1. NC: El microfanuls. ﬁnd the value of the current. it: through the capacitor at t = 0.19 seconds. I _ micro amperes. 3. Giver. the same. capacitor. if
ictt‘t = Etamperes and tacit) =11] volts fort gﬂ‘ and ict't) = El] {Ramparts for tzﬂ'l‘.
which. if any. of the following are true? F The voltage across the capacitor. trim. starts at zero. falls gradually to some negative value. then rises gradually
to zero. I: The voltage across the capacitor. ram. is zero before 1 = (l. l— The voltage across the capacitor. 1r {1}. starts at zero. rises gmrltlally to some positltre 1value. then declines
gradually to Zero.
l— The voltage across the capacitor. tctt}. stays zero for all time. httpsﬂece —onlinc.ec.iastate.edut’EEEl] l spOEtrnwf lﬂlwehqulzcgﬂs essionID=kruernpeLl U30... lflllﬂlll f“ .
@4139 mm 3
waning _I x“. ’"3.
5 QLM \‘Hixeuwm Wmmm mmwﬂ‘wxw MMMM mw.tl' If . 2H)
k_. "— a. .’_,r._}
(35%, I‘I’mA] = “‘pr M
130 — I :9 a J”
I §J yv/ an.— ~3ch L
. \ )1
be — .
\
\
 '_I l \ML F  ff#s:\
0 "IO 20 3O 40 50 60
I/{VJ i
10 — _,,a—~————
//
5 _
//
___.// I 1 I I "J hails}
O 'ICI 20 3O 40 50 E30
pImW] ; _
500 ‘— / \
400 — / 300 — / .E f
200 — \
'ICU — \\
f   _,__L R I  films}
C ' 1D 20 30 4D SCI C3
wthI
1c — 
8 _
6 _
L1 __
/
2 — /
J "u—«I/ I I I ' I ri,ws}
CI : 10 23 30 40 El} 60 Figure 5.12 The variables .i, v: p, and w ver
sus r for Example 5.5. 11 UL 12:} . mam13 Lﬁ $%Q<3:M dﬁ'“ 3: w s
13‘ 2:: 20 . 5O 5 V \LBn yz(.éﬁz3<ZD.5093 :3. Mala/LN ...
View
Full Document
 Fall '06
 Kruempel

Click to edit the document details