fa2001_exam1soln

# Fa2001_exam1soln - ECE 210f211 Analog Signal Processing Fall 2001 University of Illinois Basar Hasegawa-Johnson Munson Exam 1 Monday —~ 7:008:15

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Unformatted text preview: ECE 210f211 Analog Signal Processing Fall 2001 University of Illinois Basar, Hasegawa-Johnson, Munson Exam 1 Monday, September 24, 2001 —~ 7:008:15 PM w»: : : a Name- c:- Earl“; a was Section: 8 AM 9 AM 1 PM (circle one) Please clearly prim your name and circle your section in the boxes above. This is a closed book and closed notes exam. Calculators are not allowed. Please show all your work on Problems 2-5. Backs of pages may be used for scratch work if necessary. Good luck! Problem 1 | Problem 2 i Problem 3 ' Problem 4 I Problem 5 I Total Score 1 1. (4 p15. each, circle the correct answer) a) The value of VI is + V1 — i) 5V iv) 0V ii) 3V v) —SV av 19 b) The value of i2 is @OA iv) —1A ii) 1A v) “2A iii) 2A I/O 3 _._._. 4' ’2 2 c) The value ofi1 is + V1 " aw i) 0A iv) 12A _ ii) 2A @ 14A 0 L11 6V iii) “2A a 2V1 d) The power absorbed by the 10 V source is i) 90w iv) 40w #90 W v) 0 W iii) 60 w e) The value of RL that will maximize the power absorbed by RL is i) 4 9 iv) iii 9 ii) 10 52 ® 6 52 iii) 13 \$2 1?'77.: 4+ 4+3 2 1') V1], for the Thevenin equivaient of this circuitis i) 2V @%V ii) 1V v) 0V iii) %V __ g VS—3 2% = 1 r; wzf—Ig : a} t A \$151,, 2 “3:0 "17' 2 .— ﬁ 7, S_ g) IN for the Norton equivalent of this 49 109 circuitis a i 0A iv) 3A 18V 109 1A v) 4A iii) 2A b a l I? z {/4 "(‘ch ‘ 2. 4+5“ h) RT,1 for the Thevenin equivalent of this circuitis i) 09 @ no ii) 39 v) 159 iii) 79 2. (16pm) In the following circuit, obtain the three node equations for the three node voltages v1, v2, and V3, and write them in the form given below, by filling in the blanks. Do not solve these equations. + vx-w V1 V2 10v 0 V3 V1 “6'9”? KL 4- yr“; Node. 1—" 3 5'. T20 ~5‘V3 _ ,——=)ﬂ____, .S—I/f-S'O/(i' 3V1+VI”V2." a .516 @ 6971/if ﬂ-x/z/L'T- 5‘0 .\ “id/3 y Me 2.. V -—V ,. ’- N ’/§l+2(’i"’i)’ “‘3 +30“; :3 wry: +30%: 3W; 7-3“; (030": @ 2‘114 +45 2-390 we 3 ’4“{"3“°Jﬂ A a V 2% -2o :3“ d 3 2- 2"- 3 3 :32 21.4 ﬂrvsrxo Nodel: c ‘? )vl+< */ )vz+( ’5‘ )v3:( \$0 ) Nodez: ( 2‘7 )v1+( 4 )v2+ ( »—30 )v3= ( 3w ) NodeS: ( 2. )v1+( & )v2+( -S’ )v3=( ,20 ) 3. (10pm) In the following circuit determine the voltages V] and v0. 4. (18 pts.) Consider the following circuit where iL(0) = O. (4 pix.) 3) Describe in words what this circuit does. VOH) TJ yﬂparh‘mal 42: Mt‘zznl of L4}, (1'), (8 prs.) b) Write an expression for v00), t 2 0, in terms of Vin(t). a; .. A 0» VOW) _ ,1. M» W: Lm— L24 ,0 » A a :3 my): FizEéfr/MMM] 4— 1-14,, (’r-HT M (eﬁL/OJ) :- O ’25 d {6 p13.) c) Sketch V001), t 2 0 for the Vin(t) shown below. Vina) 5. (24 pts.) t=0 +V1— t=0 C1 + 5V C2 V2 (8 pts.) a) Write a differential equation for v26), t > 0. M :4. .. 0 C, ﬁGyQJ' 4'2. 27 k “‘2'”- J'I/Z- ‘VZ .— O “:3 (4," 42322? *7" " H'— dv’“ % #152;— “:2 0 "w mm) 6’ Vi I {4pm.} b) The time constant for this circuit is ’2 ( (31025.) c) Solve for V2(t),t>0. #- ﬂ -_-_ ﬂ 3,2(4’4'52) Léfd):5-=—>A:\S_ “(0) = 0 V2(0) = 5 {4pm} :0 vi(m)=_ﬂ€m_e_. we): ...
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## This note was uploaded on 08/08/2009 for the course ECE 210 taught by Professor Whoever during the Fall '07 term at University of Illinois at Urbana–Champaign.

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Fa2001_exam1soln - ECE 210f211 Analog Signal Processing Fall 2001 University of Illinois Basar Hasegawa-Johnson Munson Exam 1 Monday —~ 7:008:15

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