QuizX_Physics241_S09

QuizX_Physics241_S09 - C. Find Q and ~E. (2 points) c) The...

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____----. .L. _ Quiz x- 13 February 2009 Name: key ----R--ecitat-ien-Da-yt-T-imf"c--e --- --------- 1. A quantity of gas within a closed container undergoes the cycle shown below. Calculate the net heat added to the gas during one complete cycle. (3 points) LJ E /113 e /I = 0 :;; (j) - vi [F/~ r s f I ell-v) A " " tf = W ( C' Oh7;J/ e tP c!f C U: J 20~c ( ar~ Cf f i7 C Lo ~ e d ) . 'L ~ 0 L.UZ. /-tr- 5 h._. ...-. . ,. ! = j (.2 0 -5) [10 -.2. J c" Lcx-J::. U;;;'f.e . 2 10 cp = 2. a) A quantity of 1.50 moles of ideal monatomic gas (C v = 3R/2) is compressed isothermally to half of its initial volume at +35.0°c. Find Q, W and ~E for this process. (3 points) b) The gas is the cooled at constant pressure to -35.0
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Unformatted text preview: C. Find Q and ~E. (2 points) c) The gas is finally heated at constant volume to 135.0 C. What is its fmal internal energy ( _ (2 points) 0/). IV'= jPd V ~ J n:r c1 V = I/{.;:T In ~.~ (/s 0 f/uYIY}cL!) ,:( I'll -= 1.50 ~831)( (273+'3 5 J ft.-t-I/Z -.g]-w:;; -2-6.b>{1{) Ll E -= 0 C /~ 0 ftu'Y U1 c,/ ) Cf = i/V:: -:2 -b b x /0 d T . ) :>-b) . ,6 E : he v !J T = - /.3/xIO J 2 i g-x. /0 jJ q := l7e t ..6 T = LI E :-I'lL AT v d 7,63 x 107 E :::-he / = I-SO K -; I< g -3/ yC!--73 -t /35) ::; v .2. ~E=Q-W Q=mc~T T K = T c + 273 Q=mL ~E = nCv~T PV=nRT E=nCvT Cp=Cv+R Vrms = {3RT/M} 1/2 ~= 3/2kT P = nMv 2 rmsl3V R= 8.31 J/mol.K= 0.082 L.atrnlmol.K Q=nC~T...
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