ch08 - In-Class Assignment

ch08 - In-Class Assignment - 2.07 = _ LCL = Lower Control...

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_ Contents of 2.0 litre Pop Bottles X R Sample _ Sample # 1 2 3 4 5 6 Average Range Hour X 1 2.000 1.900 2.000 1.950 1.950 2.050 1.975 0.150 1 2.02 2 1.900 1.950 1.900 2.000 1.850 2.050 1.942 0.200 2 2.04 3 1.900 2.000 2.000 2.100 2.000 2.100 2.017 0.200 3 2.00 4 2.100 1.900 1.850 1.950 1.900 2.000 1.950 0.250 4 1.97 5 2.100 2.050 2.000 2.000 2.050 2.050 2.042 0.100 5 1.96 6 2.050 1.950 2.100 1.950 1.950 1.950 1.992 0.150 6 1.95 7 2.000 2.000 2.050 2.000 2.100 1.950 2.017 0.150 7 1.94 8 2.100 2.100 2.000 1.900 2.100 2.000 2.033 0.200 8 1.90 9 2.000 1.950 2.000 2.000 2.000 2.050 2.000 0.100 10 2.000 2.000 2.000 2.000 2.000 2.000 2.000 0.000 Sample Mean 1.997 0.150 Average Range = _ X = 1.997 R = 0.150 = _ UCL = Upper Control Limit = 1.997 + (.483 x .150)
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Unformatted text preview: 2.07 = _ LCL = Lower Control Limit = 1.997 - (.483 x .150) 1.92 Over the past 8 hours the following data has been collected regarding this process. Plot the sample averages on the control chart belowwhat is happening to the process? Hour 1 2 3 4 5 6 7 8 Sample Mean 2.020 2.040 2.000 1.970 1.960 1.950 1.940 1.900 2.100 0.075 UCL = 0.050 2.07 * 0.025 * 2.000 = * X = 1.997 0.075 * 0.050 * * 0.025 * LCL = 1.92 1.900 * 1 2 3 4 5 6 7 8 Hour X + A2R X - A2R 7...
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ch08 - In-Class Assignment - 2.07 = _ LCL = Lower Control...

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