quiz2 - 0 b) What is the electric field vector at a point...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Name: ________________________________ ID#: __________________________________ Physics 7D Disc. TA: ____ __________ ________________ Quiz Ch.24 Version A Date: _______________ Hour:_____________ A sphere of radius R has total charge Q distributed uniformly within its volume. The sphere is centered at the origin. a) What is the total electric flux through a spherical surface of radius r (r<R)? It is easiest to get this directly from Gauss’s law. Φ =Q enc / ε 0 The ratio of the charge enclosed in a sphere of radius r to that in a sphere of radius R is just r 3 /R 3 if r<R Φ =(r 3 /R 3 ) x Q/
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 0 b) What is the electric field vector at a point on the positive x axis a distance r from the origin (r&lt;R)? One way of solving this is to remember that the electric field at the surface is the same as that of a point charge Q at the origin and that the electric field is proportional to r for r&lt;R. E = (r/R) x (k e Q/R 2 ) i = k e Qr/R 3 i = 1/(4 ) Qr/R 3 i Another way is to use Gausss law and equate the E field times the surface area to the electric flux from part a. (r 3 /R 3 )Q/ 0 =E4 r 2 which gives the same answer when solved for E...
View Full Document

This note was uploaded on 08/22/2009 for the course PHYS 7A taught by Professor Guerra during the Spring '08 term at UC Irvine.

Ask a homework question - tutors are online