HW2_sol - 1.51 Cost per die = 6000(1500 50 = 8 Cost per...

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1.51 Cost per die = 6000 / (1500 * 50%) = 8 Cost per chip = (cost per die + cost of packaging + cost of testing) = (8 + 10) / (90%) = 20 Price = Cost per chip * 140 % = 20 * 1.4 = 28 500,000 + 20 · x = 28 · x => x = 62500 (pcs) 1.52 To complete the specific task RISC – (2P instructions * 2T) = 4 PT CISC – (P instructions * 8T) = 8 PT Therefore, RISC is better 1.54 d = a * b + a * c = a * (b + c) Therefore, 1 multiplication and 1 addition => 11 ns 4.10 The average time consuming to run 1 instruction of C1, C2 and C3 in M1 and M2 are C1: TM1 = (0.4 * 2 + 0.4 * 3 + 0.2 * 5) / 6 = 3/6 TM2 = (0.4 * 1 + 0.4 * 2 + 0.2 * 2) / 3 = 3.2/6 speedup (I1/I2) = 3.2 / 3 = 1.0667 C2: TM1 = (0.4 * 2 + 0.2 * 3 + 0.4 * 5) / 6 = 3.4 / 6 TM2 = (0.4 * 1 + 0.2 * 2 + 0.4 * 2) / 3 = 3.2 / 6 speedup (I2/I1) = 3.4 / 3.2 = 1.0625 C3: TM1 = (0.5 * 2 + 0.25 * 3 + 0.25 * 5) / 6 = 3/6 TM2 = (0.5 * 1 + 0.25 * 2 + 0.25 * 2) / 3 = 3/6 The best compiler for both I1 and I2 is C3 Since the performance of I1 and I2 are the same to use their best compiler, and all the other criteria are identical, both I1 and I2 are no difference. To purchase I1, C1 and C3 are preferred To purchase I2, C3 is preferred 4.15 Execution times of P1 : P3 = 8:1, while P2:P3 = 2:1 => P1:P2:P3 = 8:2:1 The execution time for each computer: Computer A: 8 * 2 + 2 * 20 + 1 * 200 = 256
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