Kirchoff Rule Example
PHY213
1
Example: Applying Kirchhoff’s Rules
First, define a current for
each leg of your circuit, and
draw an arrow indicating the
direction of current flow.
There are 3 unknowns:
I
1
, I
2
, and I
3
, so we will
need 3 equations to
solve for them
Note: You don’t need to get the direction of the current flow
right. This is your convention. When you solve the problem, a
negative answer simply means the current flows the other
way.
Example: Applying Kirchhoff’s Rules
Apply Kirchhoff’s junction rule
to the three wire junction at
the bottom of the diagram.
Current in = current out
Since there are 2 junctions, there
is 21 = 1 junction rule.
3
1
2
I
I
I
=
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Kirchoff Rule Example
PHY213
2
Example: Applying Kirchhoff’s Rules
1) Apply Kirchhoff’s loop
rule to the closed path in red,
traversing it clockwise
0
I
0
5
I
0
3
V
0
5
2
1
=
Ω

Ω

.
.
.
2) Apply Kirchhoff’s loop rule
to the closed path in green,
traversing it clockwise
Note the sign changes for
some of the elements
0
I
0
7
V
0
10
I
0
3
V
0
5
3
1
=
Ω

Ω

.
.
.
.
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 Summer '08
 Cao
 Physics, Current, Kirchhoff's circuit laws, Gustav Kirchhoff, 0.06W, 0.70W, 4.19W, 7.73W

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