Lectures 1 through 3 Homework Solutions Spring 2007

# Lectures 1 through 3 Homework Solutions Spring 2007 -...

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Unformatted text preview: 6-75EThe sink temperature of a Carnot heat engine, the rate of heat rejection, and the thermal efficiency are given. The power output of the engine and the source temperature are to be determined.AssumptionsThe Carnot heat engine operates steadily. Analysis(a) The rate of heat input to this heat engine is determined from the definition of thermal efficiency,Btu/min1777.8Btu/min800155.1th=→-=→-=HHHLQQQQηThen the power output of this heat engine can be determined from(29 (29hp23.1Btu/min977.8Btu/min1777.80.55thoutnet,====HQWη(b) For reversible cyclic devices we have=LHLHTTQQrevThus the temperature of the source THmust be(29R1155.6R520Btu/min800Btu/min1777.8rev===LLHHTQQT7-21CYes. This will happen when the system is losing heat, and the decrease in entropy as a result of this heat loss is equal to the increase in entropy as a result of irreversibilities.7-22CThey are heat transfer, irreversibilities, and entropy transport with mass.7-23CGreater than.7-34An insulated rigid tank contains a saturated liquid-vapor mixture of water at a specified pressure. An electric heater inside is turned on and kept on until all the liquid vaporized. The entropy change of the water during this process is to be determined....
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## This note was uploaded on 08/25/2009 for the course AET AET432 taught by Professor Rajadas during the Spring '06 term at ASU.

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Lectures 1 through 3 Homework Solutions Spring 2007 -...

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