This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Chapter 12 Radiation Heat Transfer Chapter 12 RADIATION HEAT TRANSFER View Factors 121C The view factor F i j → represents the fraction of the radiation leaving surface i that strikes surface j directly. The view factor from a surface to itself is nonzero for concave surfaces. 122C The pair of view factors F i j → and F j i → are related to each other by the reciprocity rule A F A F i ij j ji = where A i is the area of the surface i and A j is the area of the surface j. Therefore, A F A F F A A F 1 12 2 21 12 2 1 21 = → = 123C The summation rule for an enclosure and is expressed as F i j j N → = = ∑ 1 1 where N is the number of surfaces of the enclosure. It states that the sum of the view factors from surface i of an enclosure to all surfaces of the enclosure, including to itself must be equal to unity. The superposition rule is stated as the view factor from a surface i to a surface j is equal to the sum of the view factors from surface i to the parts of surface j, F F F 1 2 3 1 2 1 3 → → → = + ( , ) . 124C The crossstring method is applicable to geometries which are very long in one direction relative to the other directions. By attaching strings between corners the CrossedStrings Method is expressed as F i i j → = × ∑ ∑ Crossed strings Uncrossed strings string on surface 2 121 Chapter 12 Radiation Heat Transfer 125 An enclosure consisting of six surfaces is considered. The number of view factors this geometry involves and the number of these view factors that can be determined by the application of the reciprocity and summation rules are to be determined. Analysis A seven surface enclosure (N=6) involves N 2 2 6 = = 36 view factors and we need to determine 15 2 ) 1 6 ( 6 2 ) 1 ( = = N N view factors directly. The remaining 3615 = 21 of the view factors can be determined by the application of the reciprocity and summation rules. 126 An enclosure consisting of five surfaces is considered. The number of view factors this geometry involves and the number of these view factors that can be determined by the application of the reciprocity and summation rules are to be determined. Analysis A five surface enclosure (N=5) involves N 2 2 5 = = 25 view factors and we need to determine N N ( ) (5 ) = = 1 2 5 1 2 10 view factors directly. The remaining 2510 = 15 of the view factors can be determined by the application of the reciprocity and summation rules. 127 An enclosure consisting of twelve surfaces is considered. The number of view factors this geometry involves and the number of these view factors that can be determined by the application of the reciprocity and summation rules are to be determined. Analysis A twelve surface enclosure (N=12) involves 144 = = 2 2 12 N view factors and we need to determine N N ( ) ( ) = = 1 2 12 12 1 2 66 view factors directly. The remaining 14466 = 78 of the view factors can be determined by the application of the reciprocity and summation rules....
View
Full Document
 Spring '06
 Rajadas
 Heat Transfer, Tsurr

Click to edit the document details