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Unformatted text preview: Given: Data in Problem 51 Solution: a. The slope factor for Cr(VI) from Table 55 is 42 kg · d/mg. From Problem 51 CDI = 2.2 x 103 mg/ kg · d. The risk is then: Risk = (2.2 x 103 mg/ kg · d)(42 kg · d/mg) = 9.66 x 102 510 Characterize risk Given: tetrachloroethylene, arsenic, dichloromethane Solution: a. These are all carcinogens so calculate risk using Eqn 517 and 520 and slope factors from Table 55 Risk = (1.43 x 104 )(0.052) + (1.43 x 103 )(1.5) + (1.43 x 104 )(0.0075) Risk = 2.15 X 103 511 Cumulative probability Given: Table 52. Solution: a. Lifetime risk from driving motor vehicle (2.2 x 104 /y)(70 y) = 1.54 x 102 b. Lifetime risk from falling in home (7.7 x 105 /y)(70 y) = 5.39 x 103 c. Total Risk 1.54 x 102 + 5.39 x 103 = 2.08 x 102...
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This note was uploaded on 08/27/2009 for the course ENVE 331 taught by Professor Vigil during the Winter '08 term at Cal Poly.
 Winter '08
 VIGIL
 Environmental Engineering

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