HW8 Solution

# HW8 Solution - Chapter 4 Problem 40 Find the Thevenin...

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Chapter 4, Problem 40. Find the Thevenin equivalent at terminals a-b of the circuit in Fig. 4.107. + _ 70 V + V o 4 V o + 10 k Ω 20 k Ω c c b a I Figure 4.107 For Prob. 4.40. Solution. To obtain V Th , we apply KVL to the loop. 70 (10 20) 4 0 o kI V −+ + + = But 10 o Vk = I 70 70 1 kI I mA =⎯ →= 70 10 0 60 V Th Th kI V V + = To find R Th , one approach is to remove the 70-V source and apply a 1-V source at terminals a-b, as shown in the circuit below. V th =60.0V 1 V We notice that V o = -1 V. 11 12 0 4 0 0 . 2 5 m A o kI V I + = ⎯⎯ 21 1 0.35 mA 10 V II k =+ = 2 2.857 k 0.35 Th V Rk I == Ω = Ω b 20 Ω o 10 k Ω + _ + V o I 2 a I 1 f c + 4 V R th = 2.86k Ω 1

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Chapter 4, Problem 43. Find the Thevenin equivalent looking into terminals a - b of the circuit in Fig. 4.110 and solve for i x . The 6 ohm resistor is a load resistance. Figure 4.110 Solution. To find R Th , consider the circuit in Fig. (a). (a) 10 Ω R Th a b 10 Ω 5 Ω (b) 10 Ω 20V + 2 A 10 Ω V Th + + v a + v b 5 Ω b a R Th = 10||10 + 5 = 10.0 ohms To find V Th , consider the circuit in Fig. (b).
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## This note was uploaded on 08/27/2009 for the course EE 16200 taught by Professor Williamneal during the Fall '08 term at University of Texas.

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HW8 Solution - Chapter 4 Problem 40 Find the Thevenin...

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