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HW7 Solution

# HW7 Solution - Chapter 4 Problem 24 Use source...

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Chapter 4, Problem 24. Use source transformation to find the voltage V x in the circuit of Fig. 4.92. + 8 Ω 10 Ω 10 Ω 3 A 40 V + V x 2 V x Figure 4.92 For Prob. 4.24. Solution. Transform the two current sources in parallel with the resistors into their voltage source equivalents yield, a 30-V source in series with a 10- resistor and a 20V x -V sources in series with a 10- resistor. We now have the following circuit, I 8 Ω 10 Ω 10 Ω + _ 40 V + V x + 20V x – + 30 V We now write the following mesh equation and constraint equation which will lead to a solution for V x , 28I – 70 + 20V x = 0 or 28I + 20V x = 70, but V x = 8I which leads to 28I + 160I = 70 or I = 0.3723 A or V x = 2.98 V . 1

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Chapter 4, Problem 26. Use source transformation to find i o in the circuit of Fig. 4.94. + _ 2 Ω 5 Ω 4 Ω 3 A 6 A i o 20 V Figure 4.94 For Prob. 4.26. Solution. Transforming the current sources gives the circuit below. + _ i o 20 V + 2 Ω 15 V 5 Ω 4 Ω + _ 12 V –12 + 11i o –15 +20 = 0 or 11i o = 7 or i o = 636. mA .
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HW7 Solution - Chapter 4 Problem 24 Use source...

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