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2007 IJC Prelims Paper 2 Solution

2007 IJC Prelims Paper 2 Solution - 2007 prelim2 maths...

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2007 prelim2 maths solution H2 paper 2 pg 1 of 6 Let z be a 4 th root of 3 i + . Then 1 i 4 6 3 i 2e z π = + = 1 2 i 6 2e , 0,1, 2, 3 k k π π + = = 1 1 1 i 24 2 4 2 e , 0,1, 2, 3 k z k π π + = = 1 4 3 i z = ± 1 1 1 i 24 2 4 2 e , 0,1, 2, 3 k z k π π ± + = = 2i 2ii 2iii -4 -1 3 (1 .5 , -0.25 ) x y -0.5 1 3 ( 3, ) - -1 3 (1 .5 , -2 ) x y 2 -4 (1 .5 , 2 ) 2 - -1 2 6 (4 .5 , -8 ) x y 6
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