problem01_42 - Similarly, 4.10 cm – (1.30 cm) = 2.80 cm,...

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2.1.42: a) The x - and y -components of the sum are 1.30 cm + 4.10 cm = 5.40 cm, 2.25 cm + (–3.75 cm) = –1.50 cm. b) Using Equations (1-8) and (1-9), (5.40cm) 2 +(- 1.50 cm) 2 = 5.60 cm, arctan ( 29 40 . 5 50 . 1 + - = 344.5 o ccw. c)
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Unformatted text preview: Similarly, 4.10 cm – (1.30 cm) = 2.80 cm, –3.75 cm – (2.25 cm) = –6.00 cm. d) 2 2 ) cm . 6 ( ) cm 80 . 2 (-+ = 6.62 cm, arctan ( 29 80 . 2 00 . 6-= 295 o (which is 360 o – 65 o )....
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This note was uploaded on 08/31/2009 for the course PHYS PHYS31 taught by Professor Panunto during the Spring '09 term at Butte College.

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