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# exam1_ps_key - ENGR 111C Exam#1 October 1 2008 Name Team No...

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Unformatted text preview: ENGR 111C Exam #1 October 1, 2008 Name: Team No. ID#: Section No. Part 1 has 14 tme or false questions @ 1 point each. Part 2 has 15 multiple-choice questions @ 3 points each. Part 3 has 2 ﬁll in the blank questions @ 3 points each. Part 4 has 3 work out questions @ 10, 20, and 5 points respectively. MARK THE BEST ANSWER ON THE SCANTRON PROVIDED. Potentially Useful Constants and Conversion Factors Standard acceleration of free fall, g = 9.80665 m/s2 Gravitational conversion constant, gc : 3217M lbf‘S 1 kg = 1000 g = 0.001 tonne (metric ton) = 2.20462 16m = 35.27392 02 1 m = 100 cm 21000 mm =10" 11m = 3937111 = 3.2808 n = 1.0936 yd ~—— 0.0006214 mi 1m3 = 1000 L =10" mL 2106 cm3 = 35.3145 f9 = 264.17 gal = 1056.68 qt 1 N = 1 kg-m/s2 = 105 dynes = 105 gem/s2 = 0.22481 16.. 1 atm = 1.01325 x 105 Pa = 1.01325 bars = 760 mm Hg (00C) = 1469611541112 = 33.9 ft H20 (4°C) 1 J = 1 N-m = 107 ergs = 2.778 x 10”7 kW-h = 0.23901 cal = 0.7376 1111).: 9.486 x 10”4 Btu 1 w = 1 J/s = 0.23901 cal/s = 0.7376 f1-1bf/s = 9.486 >< 10*4 Btu/s = 1.341 x 10‘3 hp 1 mi = 5280 ft 1 acre = 43,560 ft2 1 slug = 14.594 kg 1 ft3 = 7.4805 gal 1 in = 0.0254 m 1 mi2 = 640 acre 1 it = 12 inches 1 lbf= 4.4482 N 1 ft = 0.3048 m l L = 61.02 in3 1 lbm = 0.45359 kg 1 US. ton = 200011)m 1yd=3 ft lBtu= 1054.1 lhp=746W lhp=550 ﬁlby’s 100°C = 212013 00C = 273.15 K = 32°F = 491 .670R Water density ~—~ 1 g/mL -—~ 1 g/cm‘ = 1 kg/L = 1000 kg/m3 = 8.34 lbm/gal = 62.4 16,3113 Air density (00C, 1 atm) = 1.3 g/L Air=29g H = 1; C = 12; N: 14; O = 16; Cl 2 35.5; Fe 2 55.9; S = 32 g/mol When you have ﬁnished your exam, read and sign the statement below, then turn in the examination booklet. I pledge that l have neither given nor received aid in completing this exam. 1 have followed the strictures of the Texas A&M University Code of Honor during today’s test period. Date: Signature: True/False (1 point) 1. ABET has the power /o_hcense and register professional engineers a. true b33139 2. The philosophy for ENGR 111 is to see the big picture ﬁrst so you can more easily learn the details in _ yr courses V1193 b. false 3 For a s ssful team, the Code of Cooperation should describe norms of acceptable behavior. 21%;? b. false 4 Using a genda can be an effective method of structuring meeting time 6 b. false 5. According to Rights Analysis, the actions of an engineer are morally correct if they equally respect eac human being. .true \‘ b. false 6. Utilitarianism 1s a moral theory whereby/an act is con dered morally correct if you act in your enlightened self—interest. a. true b. lse “Va/"‘3. 2 7. Synthesis is the ab1119ato~log1cally break a problem into pieces a. true W 8. Pseudocode is analgo 3“ written in a vvelfistructured, formal computer language. a. true 9. Speed ' {ﬁned as the magnitude of the velocity vector. \ b. false 10. Newton’s first law can be stated as, “In the absence of a net force applied to an object, momen‘gglegays constant. true b. false 1 l. The principal projection planes include Horizontal, Frontal, and Proﬁle. a. true b. false 12. The View chosen to be the front View is selected because it is the most descriptive View. a. true b. false 13. The dimensions of width and height can be found in the right side view. a. true b. false l4. in most applications, the text that appears on engineering drawings is 158”. a. true b. false Multiple Choice (3 points each) 15. Which of the following is the ﬁrst step in applying the Engineering Design Method? 3. Assemble a design team . e, the "best" solution. e. Identify constraints and criteria for success. 16. Which activity below most closely describes a typical engineering function of a practicing engineer? a. Develop a new fundamental economic principle that helps solve a societal problem. b. Raise money to ﬁght poverty. c. Verify th presence of pi-mesons in atomic nuclei. e. Detenmne the molecular-leve cause of an important disease. 17. Which of the following should help an effective engineering team arrive at a good solution? d. Members aggressively compete to see who comes up with the best solution e. One person should do the talking during team meetings. 18. The Code of Cooperation may be best deﬁned as a. The rules of conduct determined by the team coordinator ‘ m nt of the various roles Within a team \ , [es govenn Zg" ei'behavror of team d. A record of assigned actions e. Both b and d 19. A system of rules established by authority, society, or custom that carries penalties (cg, imprisonment ﬁnes community service) is called: (awEttquette @133 c Morals (1. Ethics e. None of the above 20. Why is it important for engineers to have a code of ethics? a. To heip avoid situations Where self—interest eouid compromise engineering judgment b. To help the puelie have conﬁdence in the profession c To help the engineer know what is expected of himfher by the profession fd; To help the engineer be honest and impartial in serving the public E 3 I ‘ 21. An algorithm is a useful problem-solving tool when the problem a Is very poorly deﬁned b Has several possible solutions some better than others based on human judgment “is very well deﬁned {Sr/Has ethical as well as engineering components e. Cannot be solved using a known equation 22. The diamond-shaped ﬂowchart symbol indicates: a. Input /output ng b. Stop / start 5;: 4/0? Branch test ’1} Process step i’ e. Process ﬂow 23. A car starts from rest and travels north. lt accelerates at a constant rate for 50 seconds, and reaches a speed of 35 miles per hour. Then it decelerates at a constant rate and stops in 5 seconds (55 seconds after starting from rest). How far did the car travel from its initial position? a. 128 ft ’ b. 569 ft c. 1283 ft {E 412 a 6. None of the above 24. The 3position p (in meters) of a moving body as a function of time t (in seconds) is given by p _. t3. The acceleration of the body at t — 3 sis: a. 36 m/s2 , 5' b. 9 m/s2 c327 m/s2 :3);st 6. none of the above 25. Select the correct right side View. given the top and front View as shown. E. None of the Above Front Work-Out Problem (10 points) 32. On a large ﬂat prairie, a cannonball is ﬁred from an initial elevation of 0.0 it at an upward angle of 30 degrees from horizontal. The muzzle velocity is 300 ft/s. Note 1: Neglect effects of air drag. Note 2: Gravitational acceleration is 32.174 ﬁ/sz. a. What is the cannonball’s elevation when it has traveled 1000 ft in the horizontal direction? b. What is the time of ﬂight, i.e., how long does it take for the cannonball to hit the ground? c. What is the maximum height of the projectile? Show all your work, including assumptions, a sketch, equations and steps you followed for solving the problem. 0:0 91):?» Vng' '3” """" V0 (’céaoc‘; gov’lLt y~(a§%oo: 25’7 81g \ S viz? : V0 Sl‘ngoc: ace ’Ft Y§l~h300: [€73 E ' S [4551111)741‘014? nyﬁler'f' 474171 h of m‘V Jraj 6 711v {#1110144 an: 2 (6 rd SC"H1H 9” I (\$1495 3;. (741% 5L. a ()umnomball’s «e/«m/m/W X; (M17 Jf V l .41 >1; Vat 1.35.. ;,:”:.7€:2W§ 25 15f, \/x 1 5 v ‘ J14 2, % ' thvt ~’2‘){: V Ff ( f , lgojkéSY\$w”Y31 (714.121 k g SW 1 977' 5’9”“ “1309955416 :— Val; 41» ”hmeéf f/Czjhi @110 : If? if ”i ? L (j %”’+\"}yct’zat v ~ £3; “5 1W1“ a: fi" .5 w “W Q g? 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exam1_ps_key - ENGR 111C Exam#1 October 1 2008 Name Team No...

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