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# exam2_ps_key - i:4 ENGR 111C Exam#2 Name Team No ID Section...

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Unformatted text preview: i' :4 ENGR 111C Exam #2 November 12, 2008 Name: Team No. ID#: Section No. .. “6843:4443. W 3‘ g g 2 Part 1 has 10 true or false questions @ 1 point each. Part 2 has 10 multiple-choice questions @ 3 points each. Part 3 has 7 multipleecboice questions @ 2 points each. Part 4 has 10 matching questions @ 2 points each Part 5 has 2 graphics work-out questions @ 8 points each Part 6 has 1 work-out question @ 10 points. MARK THE BEST ANSWER ON THE SCANTRON PROVIDED. Potentially Useful Constants and Conversion Factors Standard acceleration of free fall, g = 9.80665 111/812 R = 8.314 J/(mol‘K) = 8.314 Pa‘m3/(mol-K) . Gravitational conversion constant, go : 32- I74 1‘5 1 kg = 1000 g = 0.001 tonne (metric ton) = 2.20462 lbm = 35.27392 02 1110 = 100 em = 1000 mm =106 12m = 39.37 in = 3.2808 11: 1.0936 yd = 0.0006214 mi 11113 = 1000 L =106 mL =106 6163 = 35.3145 113 = 264.17 gal = 1056.68 qt 1 N = 1 kg-m/s2 = 105 dynes = 105 gem/32 = 0.22481 115f 1 atm = 1.01325 x 105 Pa = 1.01325 bars = 760 mm Hg (0°C) = 14.696 167162 = 33.9 ft H20 (4°C) 1 J = 1 N-m = 107 ergs = 2.778 x 10'7 kW‘h = 0.23901 6.61 = 0.7376 171-18.: 9.486 x 10“ Btu 1 w = 1 J/s = 0.23901 6617s = 0.7376 11-11373 : 9.486 x 104 Btu/s = 1.341 x 10'3 hp 1 mi = 5280 ft 1 acre = 43,560 112 1 slug = 14.594 kg 1 113 = 7.4805 gal 1 in = 0.0254 m 1 mi2 =—~ 640 acre 1 11 = 12 inches 1 113.9: 4.4482 N 1 a = 0.3048 In 1 L = 61.02 in3 1 1b... = 0.45359 kg 1 U.S. ton = 2000115m 131623 11 11316: 10541 1hpz746w 1hp=550 11-16173 100°C = 212°F 0°C : 273.15 K = 3201: = 491.67°R Water density = 1 g/mt. = 1 g/cm3 = 1 kg/L a 1000 kg/m3 : 8.34 1bm/g61 :: 62.4 162113 413.66g;in (0°C, 1 atm) = 1.3 g/L 5.411329»: H: l;C= IAN: I4; 0: 16; (31:35.5; 13133559; 8:32g/mol Mum-2M” When you have ﬁnished your exam, read and Sign the statement below, then turn in the examination booklet. I pledge that l have neither given nor received aid in completing this exam. I have followed the strictures of the Texas A&M University Code of Honor during today’s test period. g E Date: Signature: W WWWWWWWW mwneaeemwwmmwéﬁhh ﬁ§§e§§m True/False (1 pt. each) 1. The American Engineering System (ABS) is a noncoherent system of units. ég b. false 2. The Sl Base Unit for mass is the gram. a. true @3 3. The mass of a hammer is 1.00 lhm, therefore its weight on the moon is 1.00 lbf. w (a a. true 15?} {I ; (:19, 049 “3; x53. {3 g, .»r““‘ 4. The distance between two points, reported as 10.0 km, means the distance is 10,000 m 3350 m. /0. see m3? (“'0‘ / , Cell Al contains the value 10.0 and Cell Bl contains the value 5.0. Into Cell Cl, a student enters Al + Bl, which calculates the value 15 .0 when the cursor is placed in Cell Dl. a.true 31" 6. A student is interested in ﬁnding the sine of 300 so in Excel Cell Bl he places = sin(Al). When the cursor is placed in a. true 7. A correlation coefﬁcient of r = “0.98 indicates the data points are so scattered that a regression line determined by the method of least squares fits very poorly. time emu LINE/ NEE/m vs sw/JE 8. Drag force acts in a direction opposite the direction of velocity. 5 a. true ) b. false 9. Work is energy flow across a system boundary resulting from any driving force other than temperature. Cell Al he places the value 30.0 and in Cell C1, the value 0.5 appears in Cell Bl. Must” ee- {EV (Bets/Amt; h. false l0. Thermodynamics is an important subject for en gineers because it is used to determine how quickly processes occur. 3. true eeeeeeeeeee‘ee WW®§% iNMmmmmwmmwemwewmk \\ Problem Solving Multiple Choice (3 pts. each) 1 1. What force (le is required to lift with uniform velocity a mass of 100 lbm if the local acceleration of gravity is 32.174 ft/sz? a. 1.00X102l {5 . .45 x 10 f c. 3.22 x 1031bf d. 1.43 >< 10%f e. none of the above e. Mass (kiogram) d. Temperature (kelvin) e. Amount of substance (mole) 13. A circle has diameter d = 15.00 cm. The circle areaA is A=§d2 34; SL6 Pea»; When considering the proper mber of signiﬁcant digits, the answer should be reported as a. 17 em2 ﬁ ’ . 177cm C d. 18001112 e. 200 cm?“ 14. Two temperatures are deﬁned: T1=50°C and T2290°C. The temperature difference, T2 « T1 is: O {R a A 0A, a:40% Ar:?og{:~ 536C~4OC X ZEN“ c.9OR Q d. 162°R e. metre of the aboee 15. What type (if Excei chart wouid be most effective re compare various energy sourees in the United States (eii x 40%; namrai gas 2 23%; coal : 23%; nuclear : 8%; renewabies it 6%). a. x« ’seatter 0. me (1, line with Seeendary axis e. 3—D M [j : b X x: Ki f (j 2, 16. The two data points ( l, 10) and (21, 400) were taken from a straight line on a log—log plot. The equation of the line is [£732 X9 400%? m glow" y 2 14.5 x em M V y = 14.5 x 10W a. b. _ i “ C. = 10. X 10l.2lX X! A {j d- y = X x121 6. none oft 6 above , / 0 , W l («29 . . . . . _' 1 x2 -5 17. Which pair Will give a linear plot for the equation: m = 4 + 3 ? g f y 5 a My vs.x b 1/ vs. x2/4 ! yv.l/x! 6 none of the above 18. Under controlled conditions, which of the following phases of a substance can co—exist at the same:.. L time? t a. solid, liquid, plasma b. liuid gas, vapor A; _y ,ry . solid, liqul, vapor i E d. solid, liqui, gas, vapor 6, none of the above 19. If 10 mol of perfect gas is held in a constant~volume container that is initially at 1.0 atm pressure (absolute) and 25.00 C, what will be the ﬁnal pressure if the temperature is increased to 100.00 C? a3.00atm F Twp E : Aoﬂiw, C273./S~t/Oo) t; 7” / M T( * 9 C, b 4.00 at, d atm e None of the above 20. Calculate the density ofair at P x useful information) W a a. 1.29k in? 101,325 Pa (absolute) and Te 09C. (Note: The cover page has b, 1290 kgjmt c. 0.126 kgfm3 d. 1.26 x 10”? kg/m3 6, None of the above Work out (10 points) 40. A submarine designer wants to calculate the thrust required for a submarine to travel under water. The drag on the submarine can be calculated from the following equation: Fd 2" é‘PCd/jvz ‘ where Fa, = drag force (N) p = ﬂuid density (kg/m3 ) A = projected area (m2) v = velocity (m/s) For a given ﬂuid (e. g., water) this equation may be written as 2 l lJP"‘ Fa ‘ﬁ“ Fd = k CdAv 4 2 2., "‘ L Z Cg A~ V” w 2' ) a a. Using the above units, ﬁnd the numerical value and units for k. g E b. Find a new numerical value and units for k using the following units: F51: lbf A = rtz v = knots (Note: I knot = 1 nautical mile per hour. 1 nautical mile 3 1.151 statute miles = 1.151miles) C. Find the thrust (lbf) required for a submarine with a 50—ft maximum diameter traveling at 20 knots. The submarine drag coefﬁcient is 0.20, 4 N l l g M 6L kt: : £0000 Ezjsgboijr: “ﬁomzths,)z 32 W ‘1 k / “a m K a N <3, 0,2.an 7L X W: A Elia (2’33; m” 33‘ 5‘: ‘t‘ W K e W [b leieaeozu{w¢ } xrmjﬁwﬁ ’9 x w» 7 ﬁfe“ 2’ A £ x _w ﬂy; C @637; lei; \{92Xi-«(goﬂl )iwaM—H “4d; 4 t M i J i ‘ a; o "F‘riiuéﬁ {/k \ 43:“)ngij ...
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• Spring '07
• walker
• Kilogram, Three points for a win, Cell Bl, graphics work-out questions, ENGR 111C Exam, Potentially Useful Constants

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