This preview shows pages 1–5. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: lb 174 . 32 s lb in 12 ft in 2 s 60 min min ft 200 ft cm 48 . 30 g 453.6 lb cm g 1 ft 20 ) 02 . ( 2 m 2 f 2 3 m 3 = p (3) Solution (Pair Exercise 2) d Lv 2f p 2 = 2 f 2 f ft lb 100 ft lb 5 . 103 = = p ( 29 ( 29 3/2 3 3/2 ft ft /s ft LH Q 5.35 = = ( 29 2 / 5 3 in 12 ft min s 60 ft gal 7.4805 ft /s ft 5.35 5/2 3 5/2 in gal/min 4.81 = 3/2 4.81 Q LH = Solution (Pair Exercise 3)...
View
Full
Document
This note was uploaded on 09/01/2009 for the course ENGR 111 taught by Professor Walker during the Spring '07 term at Texas A&M.
 Spring '07
 walker

Click to edit the document details