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Unformatted text preview: Physics 208, Assignment 8, Solutions, 3/23/09, RT Problem 1. At Brewster’s angle the reflected direction is normal to the θ B θ t θ t 90 θ r n =1.0 1 n =1.33 2 sun eye polarization axis polaroid (a) (d) refracted direction. In this configuration it is only waves with electric field normal to the scattering plane that are reflected, so the reflected wave is linearly polarized. θ B ≡ Brewster angle = tan − 1 n 2 n 1 = 53 . 1 ◦ . (a) Angle above horizon = 90 tan − 1 1 . 33 = 36 . 9 ◦ . (b) The Efield of the fullypolarized, Brewster angle reflected, light is horizontal. Orienting the polaroid so it passes only vertical polarized light will therefore completely block the sun’s glare from the water. (c) The angle of the transmitted ray is θ t = sin − 1 n 1 sin θ B n 2 = sin − 1 . 7993 1 . 33 = 36 . 9 ◦ . (It is not a coincidence that this angle is equal to 90 θ B .) To a fish the sun appears to be 90 36 . 9 = 53 . 1 degrees above horizontal. (d) See Fig. (d). The condition for total internal reflection for light passing from water into air is 1 . 33 sin θ t = sin90 ◦ or θ t = 48 . 7 ◦ . For light passing from outside to inside the water the angle of incidence has to be slightly less than 90 ◦ which corresponds to...
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This note was uploaded on 09/01/2009 for the course PHYS 208 taught by Professor Amadeuri during the Spring '08 term at Cornell.
 Spring '08
 AMADEURI
 Polarization

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