This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Version 051/AADAD – TEST2 – Tsoi – (58020) 1 This print-out should have 15 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Starting from rest at a height equal to the radius of the circular track, a block of mass 27 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient μ ). The radius of the track is 19 m. The acceleration of gravity is 9 . 8 m / s 2 . 19 m 27 kg θ If the kinetic energy of the block at the bottom of the track is 2400 J, what is the work done against friction? 1. 1502.8 2. 2833.6 3. 1704.4 4. 2680.8 5. 3361.8 6. 2627.4 7. 4172.0 8. 3952.4 9. 1434.0 10. 1813.8 Correct answer: 2627 . 4 J. Explanation: W = W f + K W f = mg R- K = (27 kg) (9 . 8 m / s 2 ) (19 m)- (2400 J) = 2627 . 4 J . 002 10.0 points A spring is compressed between two cars on a frictionless airtrack. Car A has four times the mass of car B, M A = 4 M B , while the spring’s mass is negligible. Both cars are initially at rest. When the spring is released, it pushes them away from each other. Which of the following statements correctly describes the velocities, the momenta, and the kinetic energies of the two cars after the spring is released? Note : Velocities and momenta are given below as vectors. 1. vectorv A =- 1 3 vectorv B vectorp A =- 2 3 vectorp B K A = 4 3 K B 2. vectorv A =- vectorv B vectorp A =- 4 vectorp B K A = 16 K B 3. vectorv A =- 1 4 vectorv B vectorp A =- vectorp B K A = 1 4 K B correct 4. vectorv A =- 2 vectorv B vectorp A =- 8 vectorp B K A = 16 K B 5. vectorv A = + 1 4 vectorv B vectorp A = + vectorp B K A = 4 K B 6. vectorv A =- 1 2 vectorv B vectorp A =- 2 vectorp B K A = K B 7. vectorv A =- 4 vectorv B vectorp A =- 16 vectorp B K A = 64 K B 8. vectorv A = + 1 5 vectorv B vectorp A = + 4 5 vectorp B K A = 4 25 K B Version 051/AADAD – TEST2 – Tsoi – (58020) 2 9. vectorv A =- 1 4 vectorv B vectorp A =- vectorp B K A = 4 K B 10. vectorv A =- vectorv B vectorp A =- vectorp B K A = K B Explanation: Let : M A = 4 M B . There are no external forces acting on the cars, so their net momentum vectorp A + vectorp B is con- served. The initial net momentum is obvi- ously zero, hence after the spring is released, vectorp A + vectorp B = ; i.e., vectorp A =- vectorp B . The velocities and the kinetic energies fol- low from the momenta: vectorv = vectorp M . So given M A = 4 M B , it follows that vectorv A =- 1 4 vectorv B . Likewise, K = 1 2 M vectorv 2 = vectorp 2 2 M . Since vectorp A =- vectorp B , K A = 1 4 K B . 003 (part 1 of 2) 10.0 points A football is thrown hard horizontally and it hits and sticks in a cart that is on a track at position A in the diagram. The cart with the football in it then moves along the hilly frictionless track to position B, where the cart stops....
View Full Document

{[ snackBarMessage ]}