HW5SupplementalSolutions

HW5SupplementalSolutions - So E = No of Batteries Rated...

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#2 The resistence of each piece is31/3 ohm working by parts .If you connect two in parallel the resistance is 31/6 Now connecting this two with the third you get R = (31/6*31/3)/(31/2)= 31/9 ohm #9-13 1. Power = Work / Time = Force * Displacement / Time = Force * Velocity. Convert to proper units. So P = . .. Watts . ........................ 41667 2. Battery ratings are so many Amperes of electric current for 1 hour or 3600s. Charge delivered: Coulombs = Rated Current * Rated Time, so for 10 batteries, total charge delivered is: C = 10 * . .. Coulombs . ............... 5760000 3. Total energy delivered (this is from rating, not actual) E in Joules = Rated Power in Watts * Rated Time Rated Power in Watts = Rated Voltage Volts * Rated Current Amperes
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Unformatted text preview: So E = No. of Batteries * Rated Voltage * Rated Current * Rated Time = . .. Joules. ............... 69120000 4. Total Available Energy E = . .. Joules from 3. Power Consumption P = . ..Watts from 1. Total Time of running before recharging = E / P = . .. seconds . ........................ 1659 At 100 km/hr it goes . ... km . ............. 460.8 5. Energy delivered by the batteries can also be expressed in E in Watt-hours = Rated Power in Watts* Rate Time in hour At a charging price of R cents / kwh, total cost of charging 10 batteries: cost = E in Watt-hours * R /1000 = . .. cents . ................. 172.8...
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