HW7Solutions - where l = length of coil and w = width. The...

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Question #1
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Question #2 Let's deal with magnitudes first The B field for a long straight wire is B=uI/(2πr) 13.5E-9=(4πE-7)I/(2π8.1) ==> I=0.55 A Now, let's consider direction. Because the direction of the field points north, east of the source, the right-hand rule would have the current flowing from top to bottom. Question #3 Question #4 It'shard to tell from the diagram what the geometry ofthe problem is. However, you can proceed by realizing that there is an induced voltage (emf) in the loops givne by: V = -d(BA)/dt where B = magnetic field and A = area of the coils. Note that A is 2*l*w
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Unformatted text preview: where l = length of coil and w = width. The "2" is due to the fact that there are two coils. Since A is constant and B is time varying we can wrtie V = - 2*l*w d B/dt = -2*l*w*0.001 (d B/dt = d (0.001 t)/dt = 0.001) Now the current flowing is just: I = V/R R = resistance of coils. But R = p*L where p = 0.0519 Ohms/m and L = total length of wire = 2*(2*l +2*w) = 4(l+w) Putting all together: I = -2*l*w*0.001/(p*4(l+w)) = -0.001*l*w/(p*(l+w)) Question #5-#6...
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This note was uploaded on 09/03/2009 for the course PHY PHY 2049 taught by Professor Robertr.criss during the Fall '08 term at University of South Florida - Tampa.

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HW7Solutions - where l = length of coil and w = width. The...

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