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Unformatted text preview: where l = length of coil and w = width. The "2" is due to the fact that there are two coils. Since A is constant and B is time varying we can wrtie V =  2*l*w d B/dt = 2*l*w*0.001 (d B/dt = d (0.001 t)/dt = 0.001) Now the current flowing is just: I = V/R R = resistance of coils. But R = p*L where p = 0.0519 Ohms/m and L = total length of wire = 2*(2*l +2*w) = 4(l+w) Putting all together: I = 2*l*w*0.001/(p*4(l+w)) = 0.001*l*w/(p*(l+w)) Question #5#6...
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This note was uploaded on 09/03/2009 for the course PHY PHY 2049 taught by Professor Robertr.criss during the Fall '08 term at University of South Florida  Tampa.
 Fall '08
 RobertR.Criss
 Physics

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