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2
2
Vr
z
π
=
where
z
is the ice thickness. Since there are 10
3
m in 1 km and 10
2
cm in 1 m, we have
()
32
5
10 m
10 cm
2000km
2000
10 cm.
1km
1m
r
§·
§
·
==
×
¨¸
¨
¸
©¹
©
¹
In these units, the thickness becomes
2
2
10 cm
3000m
3000
10 cm
z
=
×
which yields
(
)
2
52
2
2
3
2000
10 cm
3000
10 cm
1.9
10
cm .
2
V
π
=×
×
=
×
7. The volume of ice is given by the product of the semicircular surface area and the
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics

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