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(a) Multiplying
f
by the timeinterval
t
= 7.00 days (which is equivalent to 604800 s, if
we ignore
significant figure
considerations for a moment), we obtain the number of
rotations:
()
3
1 rotation
604800 s
388238218.4
1.55780644887275
10
s
N
−
§·
==
¨¸
×
©¹
which should now be rounded to 3.88
×
10
8
rotations since the timeinterval was
specified in the problem to three significant figures.
(b) We note that the problem specifies the
exact
number of pulsar revolutions (one
million). In this case, our unknown is
t
, and an equation similar to the one we set up in
part (a) takes the form
N
=
ft
, or
6
3
1rotation
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.
 Spring '06
 Stoler
 Physics

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