ch01-p020 - 20. The density of gold is = m 19.32 g = =...

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(a) We take the volume of the leaf to be its area A multiplied by its thickness z . With density ρ = 19.32 g/cm 3 and mass m = 27.63 g, the volume of the leaf is found to be V m == 1430 .. cm 3 We convert the volume to SI units: () 3 36 3 1m 1.430 cm 1.430 10 m . 100 cm V §· × ¨¸ ©¹ Since V = Az with z = 1 × 10 -6 m (metric prefixes can be found in Table 1–2), we obtain A = × × = 10 11 0 6 6 . m m m 3 2 (b) The volume of a cylinder of length
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