ch01-p024 - is from 3 2 10 to 4 2 10 m 3 . (b) Using the...

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of this problem is due to the fact that each liter has a mass of one kilogram when water is at its normal density (under standard conditions). 24. (a) The volume of the cloud is (3000 m) π (1000 m) 2 = 9.4 × 10 9 m 3 . Since each cubic meter of the cloud contains from 50 × 10 6 to 500 × 10 6 water drops, then we conclude that the entire cloud contains from 4.7 × 10 18 to 4.7 × 10 19 drops. Since the volume of each drop is 4 3 (10 × 10 6 m) 3 = 4.2 × 10 15 m 3 , then the total volume of water in a cloud
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Unformatted text preview: is from 3 2 10 to 4 2 10 m 3 . (b) Using the fact that 3 3 3 3 1 L 1 10 cm 1 10 m = = , the amount of water estimated in part (a) would fill from 6 2 10 to 7 2 10 bottles. (c) At 1000 kg for every cubic meter, the mass of water is from two million to twenty million kilograms. The coincidence in numbers between the results of parts (b) and (c)...
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This note was uploaded on 09/03/2009 for the course PHYS 1200 taught by Professor Stoler during the Spring '06 term at Rensselaer Polytechnic Institute.

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