ch01-p029 - d . Thus, d = 25 m. The volume of a small part...

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29. The volume of the section is (2500 m)(800 m)(2.0 m) = 4.0 × 10 6 m 3 . Letting “ d stand for the thickness of the mud after it has (uniformly) distributed in the valley, then its volume there would be (400 m)(400 m) d . Requiring these two volumes to be equal, we can solve for
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Unformatted text preview: d . Thus, d = 25 m. The volume of a small part of the mud over a patch of area of 4.0 m 2 is (4.0) d = 100 m 3 . Since each cubic meter corresponds to a mass of 1900 kg (stated in the problem), then the mass of that small part of the mud is 5 1.9 10 kg ....
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